Xcode项目不使用NSKeyedArchiver存档，但游乐场做

Question

我有使用NSCoding和NSObject归档的一些问题。这在Playground中完美无瑕。但在Xcode中似乎并不适用。有人可以帮我解决这个问题吗？

每次我打电话：

NSKeyedArchiver.archiveRootObject(person, toFile: "person") 

它的工作原理，并在游乐场返回true，但在项目返回false。我不使用模拟器。

我一直在寻找相同类型的问题，但我似乎无法找到任何与此相关的任何内容。

class Person: NSObject, NSCoding { 

private var _name: String = "name" 
private var _birthdate: Date = Date() 
private var _income: Int = -1 
private var _wealth: Int = -1 

var name: String { 
    get { return _name } 
    set (newName) { _name = newName } 
} 
var birthdate: Date { 
    get { return _birthdate } 
    set (newBirthdate) { _birthdate = newBirthdate } 
} 
var income: Int { 
    get { return _income } 
    set (newIncome) { _income = newIncome } 
} 
var wealth: Int { 
    get { return _wealth } 
    set (newWealth) { _wealth = newWealth } 
} 

override init(){} 

required convenience init(coder unarchiver: NSCoder) { 

    self.init() 

    if let name = unarchiver.decodeObject(forKey: "name") as? String { 
     self.name = name 
    } 
    if let birthdate = unarchiver.decodeObject(forKey: "birthdate") as? Date { 
     self.birthdate = birthdate 
    } 
    let income = unarchiver.decodeInteger(forKey: "income") 
    self.income = income 

    let wealth = unarchiver.decodeInteger(forKey: "wealth") 
    self.wealth = wealth 

} 

func encode(with archiver: NSCoder) { 

    archiver.encode(name, forKey: "name") 
    archiver.encode(birthdate, forKey: "birthdate") 
    archiver.encode(income, forKey: "income") 
    archiver.encode(wealth, forKey: "wealth") 
} 
} 

然后我创建一个人并归档它。

let person = Person() 
NSKeyedArchiver.archiveRootObject(person, toFile: "person") 

Answer 1

您需要在Person类中对init进行一个小的编辑。取出convenience关键字和替换self.init()与super.init()：

class Person: NSObject, NSCoding { 

    private var _name: String = "name" 
    private var _birthdate: Date = Date() 
    private var _income: Int = -1 
    private var _wealth: Int = -1 

    var name: String { 
     get { return _name } 
     set (newName) { _name = newName } 
    } 
    var birthdate: Date { 
     get { return _birthdate } 
     set (newBirthdate) { _birthdate = newBirthdate } 
    } 
    var income: Int { 
     get { return _income } 
     set (newIncome) { _income = newIncome } 
    } 
    var wealth: Int { 
     get { return _wealth } 
     set (newWealth) { _wealth = newWealth } 
    } 

    override init() {} 

    required init(coder unarchiver: NSCoder) { 

     super.init() 

     if let name = unarchiver.decodeObject(forKey: "name") as? String { 
      self.name = name 
     } 
     if let birthdate = unarchiver.decodeObject(forKey: "birthdate") as? Date { 
      self.birthdate = birthdate 
     } 
     let income = unarchiver.decodeInteger(forKey: "income") 
     self.income = income 

     let wealth = unarchiver.decodeInteger(forKey: "wealth") 
     self.wealth = wealth 

    } 

    func encode(with archiver: NSCoder) { 

     archiver.encode(name, forKey: "name") 
     archiver.encode(birthdate, forKey: "birthdate") 
     archiver.encode(income, forKey: "income") 
     archiver.encode(wealth, forKey: "wealth") 
    } 
} 

一旦你这样做，你可以调用，无论你想（我做到了，我viewDidLoad中只是用于测试和它的工作）给它这样的路径归档：

let person = Person() 
let path = FileManager.default.urls(for: .documentDirectory, in: .userDomainMask).first!.appendingPathComponent("person").path 
let personWasUploaded: Bool = NSKeyedArchiver.archiveRootObject(person, toFile:path) 
print(path) 
print("person uploaded: \(personWasUploaded)")