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我想用正则表达式监视charector。e.keycode在firefox 19.0.2中未定义,chrome 25.0.1364.172 m,IE 8
$('#searchContent').keyup(function(e){
e = e || window.event;
var patt =/\w/g;
var key = String.fromCharCode(e.keyCode);
console.log ("key " + key + e.keycode+ " is pressed!!");
if(e.keycode != 8 && e.keyCode != 46){ //Will return if printable char is not typed. But the datagrid will still refresh on pressing backspace.
console.log ("key " + key+ e.keycode + "is about to take test!!");
if(!patt.test(key)){
console.log ("key " + key+e.keycode + "is failed!!");
return;
}
console.log ("key " + key +e.keycode+ "is pressed passes the test!!");
}
else{
console.log ("backspace or delete has ByPasses the conditoin!!");
}
// other operations....
}
//Result of my log. INPUT : RIS(<-backspace)
key R undefined is pressed!! index_tab.php:173
key R undefined is about to take test!! index_tab.php:176
key R undefined is pressed passes the test!! index_tab.php:181
key I undefined is pressed!! index_tab.php:173
key I undefined is about to take test!! index_tab.php:176
key I undefined is pressed passes the test!! index_tab.php:181
key S undefined is pressed!! index_tab.php:173
key S undefined is about to take test!! index_tab.php:176
key S undefined is pressed passes the test!! index_tab.php:181
key undefined is pressed!! index_tab.php:173 //here backspace was pressed
key undefined is about to take test!! index_tab.php:176
key undefined is failed!!
案例是敏感这里,MHM。 – jolt 2013-03-22 09:03:03
'e.which'在jQuery中被标准化,所以大多数人都使用它! – adeneo 2013-03-22 09:05:16