SQL查询SUM从SELECT COUNT语句与UNION的表格

Question

我目前正在试图总结一个MySQL语句的结果，它给了我几个不同的表的行数。

我已经研究了关于这个问题的每一个stackoverflow的解决方案。不幸的是，我无法弄清楚我的案例的正确语法。

我的结果工作陈述不概括：

SET @shipmentId=456; 
SELECT 
     (SELECT COUNT(*) FROM Table1 WHERE ShipmentID = @shipmentId) 
     UNION ALL 
     (SELECT COUNT(*) FROM Table2 WHERE ShipmentID = @shipmentId) 
     UNION ALL 
     (SELECT COUNT(*) FROM Table3 WHERE ShipmentID = @shipmentId) 
     UNION ALL 
     (SELECT COUNT(*)FROM Table4 WHERE ShipmentID = @shipmentId) 
     UNION ALL 
     (SELECT COUNT(*)FROM Table5 WHERE ShipmentID = @shipmentId); 

在我看来，这应该是最近的一个正确的解决办法，但我不知道（试过很多变种）：

SET @shipmentId=456; 
SELECT SUM(MeasuredValues) FROM 
    SELECT(
     (SELECT COUNT(*) FROM Table1 WHERE ShipmentID = @shipmentId) AS MeasuredValues 
     UNION ALL 
     (SELECT COUNT(*) FROM Table2 WHERE ShipmentID = @shipmentId) AS MeasuredValues 
     UNION ALL 
     (SELECT COUNT(*) FROM Table3 WHERE ShipmentID = @shipmentId) AS MeasuredValues 
     UNION ALL 
     (SELECT COUNT(*)FROM Table4 WHERE ShipmentID = @shipmentId) AS MeasuredValues 
     UNION ALL 
     (SELECT COUNT(*)FROM Table5 WHERE ShipmentID = @shipmentId) AS MeasuredValues) t1;  

在此先感谢您的帮助。

已经尝试过以下链接： StackOverFlow Solution1

StackOverFlow Solution2

Answer 1

你可以只是简单总结一下你的选择：

SET @shipmentId=456; 
SELECT 
    (SELECT COUNT(*) FROM Table1 WHERE ShipmentID = @shipmentId) 
+ 
    (SELECT COUNT(*) FROM Table2 WHERE ShipmentID = @shipmentId) 
+ 
    (SELECT COUNT(*) FROM Table3 WHERE ShipmentID = @shipmentId) 
+ 
    (SELECT COUNT(*) FROM Table4 WHERE ShipmentID = @shipmentId) 
+ 
    (SELECT COUNT(*) FROM Table5 WHERE ShipmentID = @shipmentId);