如何将数组转换为Doctrine中的JSON?如何在Doctrine中编码JSON数组?
到目前为止,我已经试过this.Here是我的代码:
require_once ("../Users.php");
require_once("../../test/doctrine/cli-config.php");
require_once "../../test/doctrine/bootstrap.php";
$user_list = array();
$usersRepository = $entityManager->getRepository('Users');
$users = $usersRepository->findAll();
echo "<pre>";
print_r($users);
foreach ($users as $user)
{
$user_list[] = array('user_list'=>$user);
}
json_encode($user_list)
的的print_r()部分返回我:
Array
(
[0] => Users Object
(
[id:Users:private] => 1
[lastName:Users:private] => User1
[firstName:Users:private] => Test1
[city:Users:private] => ABC
[country:Users:private] => XYZ
[email:Users:private] => [email protected]
)
[1] => Users Object
(
[id:Users:private] => 2
[lastName:Users:private] => User2
[firstName:Users:private] => Test1
[city:Users:private] => ABC
[country:Users:private] => XYZ
[email:Users:private] => [email protected]
)
)
[{"user_list":{}},{"user_list":{}}]
看到JSON响应为空。任何人都可以帮助我吗?
我推荐使用[** JMS /串行**](https://github.com/schmittjoh/serializer)导出您的实体 – Touki
@Touki我得到这些错误 未定义的变量:序列化程序 致命错误:调用非对象的成员函数serialize() –
请花时间正确地[阅读文档](http://jmsyst.com/libs/serializer),然后转到[搜索你的错误](http://stackoverflow.com/a/12769983/1607098)。我很确定你没有遵循安装步骤,这就是为什么你得到这个错误。 – Touki