有2台帮助与SQL查询
1st {id_city,name }
2nd table {id_ctz,name,sname,age,id_city}
需要进行选择的全部信息(名称(市),姓名,SNAME,年龄)的人具有相同名称的年龄accending?
曾尝试:
select city.name,citizen.name,age
from citizen,city where city.id_city = citizen.id_city and citizen.name = '%s'
order by age asc
输入varible是名
那么,你有什么尝试? – 2010-07-10 18:27:41
select city.name,citizen.name,年龄来自市民,city.id_city = citizen.id_city和citizen.name ='%s'按年龄排序asc – alexandr 2010-07-10 18:31:35
@alexandr:那有什么问题? – 2010-07-10 18:32:00