在UPPER中搜索前两个字符的字段

Question

我在查询具有ONeil值的sql服务器表。我的目标是为查询的数据添加一个撇号。我知道这将是更容易从源（PHP）修复了问题，但必须对这些脚本

表结构没有接入，

ID  First_Name  Last_Name 
1  John   ONEil 
2  Sam   OMally 
3  Sarah   OConner 

Answer 1

你可以做的第一2个字符的字符串比较，找出哪些记录有姓氏以2个大写字母，像这样开头：

create table test (Last_Name varchar(50)); 
insert into test values ('ONEil'), ('OMally'), ('OConner'), ('Michaels'); 

select * from test where hex(left(Last_Name, 2)) = hex(upper(left(Last_Name,2))) 

Result: 
Last_Name 
ONEil 
OMally 
OConner 

要更新这些记录，你可以这样做：

update test 
set Last_Name = concat(left(Last_Name, 1), '''', mid(Last_Name, 2, length(Last_Name)-2)) 
where hex(left(Last_Name, 2)) = hex(upper(left(Last_Name,2))) 

select * from test; 

Results: 
Last_Name 
O'NEi 
O'Mall 
O'Conne 
Michaels 

SQLFiddle例如：http://sqlfiddle.com/#!9/8165e4/2

Answer 2

在搜索字符串，前两个字符是大写：

LiveDemo

CREATE TABLE #mytable(
    ID   INTEGER NOT NULL PRIMARY KEY 
    ,First_Name VARCHAR(5) NOT NULL 
    ,Last_Name VARCHAR(7) NOT NULL 
); 
INSERT INTO #mytable(ID,First_Name,Last_Name) VALUES (1,'John','ONEil'); 
INSERT INTO #mytable(ID,First_Name,Last_Name) VALUES (2,'Sam','OMally'); 
INSERT INTO #mytable(ID,First_Name,Last_Name) VALUES (3,'Sarah','OConner'); 
INSERT INTO #mytable(ID,First_Name,Last_Name) VALUES (4,'Sarah','Smith'); 


SELECT 
    ID, 
    First_Name, 
    Last_Name = CONCAT(LEFT(Last_Name, 1), '''', RIGHT(Last_Name, LEN(Last_Name)-1)) 
FROM #mytable 
WHERE Last_Name LIKE '[A-Z][A-Z]%' COLLATE Latin1_General_BIN; 

输出：

╔════╦════════════╦═══════════╗ 
║ ID ║ First_Name ║ Last_Name ║ 
╠════╬════════════╬═══════════╣ 
║ 1 ║ John  ║ O'NEil ║ 
║ 2 ║ Sam  ║ O'Mally ║ 
║ 3 ║ Sarah  ║ O'Conner ║ 
╚════╩════════════╩═══════════╝ 

Answer 3

表

mysql> select * from names where LEFT(last_name, 2) = UPPER(LEFT(last_name, 2)); 
+-----------+ 
| last_name | 
+-----------+ 
| Michael | 
| Blah  | 
| ONeil  | 
+-----------+ 

更新查询

update names 
set last_name = concat(left(last_name, 1), '\'', right(last_name, length(last_name)-1)) 
where binary left(last_name, 2) = upper(left(last_name, 2)) 
    and binary upper(left(last_name, 3)) <> left(last_name, 3); 

结果

+-----------+ 
| last_name | 
+-----------+ 
| Michael | 
| Blah  | 
| O'Neil | 
+-----------+ 

Answer 4

如果你想更新姓氏场，其中1号2字符大写包括一个单引号的话，我会发出更新查询：

update tablename set last_name=left(last_name,1) + char(146) + substring(last_name,2) 
where binary upper(left(last_name,2))=left(last_name,2) 

Answer 5

您的问题需要多一点澄清，但我想象一下，如果前两个字符是大写，但是如果不是则返回Oneal，而您想要返回O'Neil而不是ONeil？

如果是这样，这是一个使用整理，的情况下，上一个选项，左，右......

select id, first_name, last_name, 
    case when left(last_name,2) = upper(left(last_name,2)) 
            collate SQL_Latin1_General_CP1_CS_AS 
     then left(last_name,1) + '''' + right(last_name, len(last_name) - 1) 
     else last_name 
    end as new_last_name 
from yourtable 

• SQL Fiddle Demo

Answer 6

可以使用两个功能来做到这一点。

第一个是SUBSTRING（切割前两个字母） ，第二个是ASCII （大写开始从41至5A的ASCII数）它可以帮助你找到两个第一大写字母。

了解更多：

https://msdn.microsoft.com/en-us/library/ms187748.aspx

https://msdn.microsoft.com/en-us/library/ms177545.aspx