比较XML元素的文本内容和子元素在Java中

Question

添加到特定节点

我有一个包含以下列格式

Dr.|ricardo bettati 
Prof. Dr.-Ing.|Helmut sperling 
miss|angela link 

首先，我很分裂与|。我的内容标题和全名的ArrayList会获得标题和全名。然后我分裂fullnames与空间得到firstname和familyname.

现在我有3串

其中包含从上述列表 字符串姓标题

字符串标题\; 字符串familynames;

下一个任务是，我有检查存在XML的文本内容与上面的字符串firstname和familyname。这里是存在XML

<person> 
<name> 
    <firstname>Jean-Luc</firstname> 
    <familyname>DeLorme</familyname> 
</name> 
</person> 
<person> 
<name> 
    <firstname>Dave</firstname> 
    <familyname>Sperling</familyname> 
</name> 
</person> 
<person> 
<name> 
    <firstname>Helmut</firstname> 
    <familyname>sperling</familyname> 
</name> 
</person> 

如果firstname和familyname contets与上面的文字内容相匹配XML元素<firstname>,<familyname>然后我必须创建一个名为<title>的元素，并在我的列表中添加相应的标题。我的XML应该看起来像下面这样：

<person> 
<name> 
    <firstname>Jean-Luc</firstname> 
    <familyname>DeLorme</familyname> 
</name> 
</person> 
<person> 
<name> 
    <firstname>Dave</firstname> 
    <familyname>Sperling</familyname> 
</name> 
</person> 
<person> 
<name> 
    **<title>Prof. Dr.-Ing.>/title>** 
    <firstname>Helmut</firstname> 
    <familyname>sperling</familyname> 
</name> 
</person> 

我试图用下面的代码

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); 
     dbf.setValidating(false); 
     DocumentBuilder db = dbf.newDocumentBuilder(); 
     Document doc = db.parse(new FileInputStream(new File("Final-Results.xml"))); 
     Element element = doc.getDocumentElement(); 
     NodeList list = doc.getElementsByTagName("person"); 
     for (int i=0;i<titles.size();i++) { //Title is my arraylist 
      String names = (String) titles.get(i); 
      String[] content=names.split("\\|"); 
      String title=content[0]; 
      String[] fullname=content[1].split("\\s+"); 
      String firstname=fullname[0]; 
      String familyname=fullname[1]; 
      for (int n = 0; n < list.getLength(); n++) { 

        Node node = list.item(n); 
        if ("firstname".equals(node.getNodeName()) && node.getTextContent().equals(firstname)) { 
        System.out.println("haii"); 
        } 
      } 
     } 

但我得怎么回事儿和检查的文本内容，并建立在特定地点的节点？

Answer 1

 
Child node appending: 
    Element childElement = doc.createElement("title"); 
    // set attributes, etc 
    node.appendChild(childElement); 

的代码可以使用XPath被简化，如：

String xPathExpression = "*/person/name[firstname/text() = 'Helmut' and familyname/text() = 'sperling']"; 
    XPath path = XPathFactory.newInstance().newXPath(); 
    NodeList nl = (NodeList) path.evaluate(xPathExpression, doc, XPathConstants.NODESET); 
    for (int i = 0; i < nl.getLength(); i++) { 
     Element childElement = doc.createElement("title"); 
     childElement.appendChild(doc.createTextNode("Dr.")); 
     nl.item(i).insertBefore(childElement,((Element)nl.item(i)).getFirstChild()); 
    } 

如果指定例如运行代码，结果是：

<?xml version="1.0" encoding="UTF-8" standalone="no"?><result> 
<person> 
<name> 
    <firstname>Jean-Luc</firstname> 
    <familyname>DeLorme</familyname> 
</name> 
</person> 
<person> 
<name> 
    <firstname>Dave</firstname> 
    <familyname>Sperling</familyname> 
</name> 
</person> 
<person> 
<name><title>Dr.</title> 
    <firstname>Helmut</firstname> 
    <familyname>sperling</familyname> 
</name> 
</person> 
</result>