我不知道,如果在Linux是使任何不同,但我已经在网上发现这一点:按任意键继续在Linux下C++
cout << "Press Enter to Continue...";
cin.ignore(numeric_limits<streamsize>::max(),'\n');
应该是足够的,与#include<limits>
当然在头部。
但是,它似乎并没有在我的程序中工作。
它编译,它运行,但它不会等待。
基本上,我有一个菜单,这导致了一个方法调用来显示屏幕上的人列表。我希望在系统返回到菜单之前暂停该列表。
这是从菜单中选择我的代码:
//Manager's Menu
void SelectionPage::showManagerMenu(){
char option;
while(true)
{
system("clear"); //Clears the terminal
cout<<" Flat Manager's Menu"<<endl<<endl; //Display manager's menu
cout << "Select Manager option" << endl;
cout << "a) Add a new Flat Member" << endl;
cout << "b) Delete an existing Flat Member" << endl;
cout << "c) List Flat Members" << endl;
cout << "d) Duties" <<endl;
cout << "e) Resources" <<endl;
cout << "f) Reset System" <<endl;
cout << "q) Exit" << endl;
cout << "make selection: ";
cin >> option;
switch(option) { //Takes the user to the corresponding menu or method
case 'a': system("clear");
memberList.addNewFlatMember(points);
break;
case 'b': system("clear");
memberList.deleteFlatMember();
break;
case 'c': system("clear");
memberList.listFlatMembers();
break;
case 'd': system("clear");
showDutiesMenu();
break;
case 'e': system("clear");
showResourcesMenu();
break;
case 'f': //reset();
break;
case 'q': exit(0);
default: cout << "Option not recognised: " << option << endl;
showManagerMenu();
}
}
}
我要选择的选项为C),这导致:
//Show the current flat population
void MemberManagement::listFlatMembers(){
cout<<" Member List"<<endl<<endl;
importFlatMembers(); //get flat member info from file
for(int count = 0; count<flatMemberList.size(); count++){
cout << count+1<<". "<<flatMemberList[count].getName() << endl;
}
cout << "Press any key to Continue...";
cin.ignore(numeric_limits<streamsize>::max(),'\n');
return;
}
如果你想看到我的代码的任何其他位
,随时让我知道。
在此先感谢。
Rob's Rule#47:当你的意思是''\ n''时,千万不要说'endl'。请参阅http://stackoverflow.com/questions/5492380/what-is-the-c-iostream-endl-fiasco –