2016-04-29 24 views
0

我正在使用函数get_headers($ url,1)获取网站的标题http://www.sportsmalayalam.com/输出如下。它没有'内容编码'但是当我通过谷歌浏览器检查同一网站的标题时,它显示的内容编码为gzip。get_headers()不在PHP中显示内容编码

运行时:print_r(get_headers($ url,1));

Array ( 
[0] => HTTP/1.1 200 OK 
[1] => Date: Fri, 29 Apr 2016 10:35:20 GMT 
[2] => Content-Type: text/html; charset=UTF-8 
[3] => Connection: close 
[4] => Set-Cookie: __cfduid=d564038ff91bf8887430482dc8a8cf74b1461926119; expires=Sat, 29-Apr-17 10:35:19 GMT; path=/; domain=.sportsmalayalam.com; HttpOnly 
[5] => X-Powered-By: PHP/5.5.9-1ubuntu4.16 
[6] => Set-Cookie: PHPSESSID=empthbjqo968ak1a3cbaa6jr67; path=/ 
[7] => Expires: Thu, 19 Nov 1981 08:52:00 GMT 
[8] => Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0 
[9] => Pragma: no-cache 
[10] => Link: ; rel="https://api.w.org/" 
[11] => Link: ; rel=shortlink 
[12] => Vary: Accept-Encoding, Cookie 
[13] => Server: cloudflare-nginx 
[14] => CF-RAY: 29b21b47261e2fab-MAA 
) 

从谷歌浏览器: enter image description here

回答

4

比较请求头。 Chrome可能会发送一个Accept-Encoding标头,表示在PHP没有的情况下,gzip的响应是OK的。因此,服务器的响应方式不同。

+0

所以我必须发送请求说我可以处理gzip? –

+1

是的。默认是“不压缩”,客户端需要明确地*请求它。 – Piskvor

+0

我该如何发送? –