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为什么我的AJAX功能无法与get方法阿贾克斯提交多值
<script language="javascript" type="text/javascript">
<!--
//Browser Support Code
function ajaxFunction(){
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
document.getElementById("emailconfirm").innerHTML= ajaxRequest.responseText;
}
}
ajaxRequest.open("GET", "Atest.php?<?php echo $PDFPassingArray ?>?Email="+ document.getElementById("email").value, true);
ajaxRequest.send(null);
}
提交这两个值我希望函数提交数组$ pdfpassingArray,这是一个html_build_query和形式电子邮件elemment ID。目前我只能修改$ pdfPassingarray值,但不能修改Email值。所以我的问题,我做这部分的权利
ajaxRequest.open("GET", "Atest.php?<?php echo $PDFPassingArray ?>?Email="+ document.getElementById("email").value, true);
我的形式
<form name='myForm'>
<input name="email" id="email"type="text" />
<input name="button" onclick="ajaxFunction()" type="button" />
</form>
这真的是你的[上一个问题]的一部分(http://stackoverflow.com/questions/12270099/pass-a-variable-to-an-ajax-function)? –