-2
我有以下的JSON文件嵌套的JSON PHP解码
{
"username”: “userabc”,
“locations”: [
{
“locationId": "2123",
“locationName": "Test Site",
“setupDate”: "0000-00-00",
“dataType”: {
“book”: [
{
“bookId": “1257245",
“information”: “Infotag 181”,
“addedDate": "0000-00-00 00:00:00"
},
{
“bookId": “4257245",
“information”: “Infotag 11”,
“addedDate": "0000-00-00 00:00:00"
},
{
“bookId": “2227242”,
“information”: “Infotag 181”,
“addedDate": "0000-00-00 00:00:00"
}
],
“tape”: [
{
“tapeId": “1220”,
“information”: “Infotag 181”,
“addedDate": "0000-00-00 00:00:00"
},
{
“tapeId": “1320”,
“information”: “Infotag 181”,
“addedDate": "0000-00-00 00:00:00"
}
],
“record”: [
{
“recordId": “a21322”,
“information”: “Infotag 181”,
“addedDate": "0000-00-00 00:00:00"
},
{
“recordId": “b213222”,
“information”: “Infotag 181”,
“addedDate": "0000-00-00 00:00:00"
}
],
"virtual": [
{
“virtId": "2123",
“information”: "57235",
“addedDate”: "0000-00-00 00:00:00",
}
]
}
}
]
}
我目前正在试图访问的嵌套部分(计数bookIDs的数量)。我已经完成了以下操作,可以打印locationName,但无法打印bookId,我不确定我要出错的地方。
$obj = json_decode($json,true);
foreach($obj['locations'] as $chunk) {
$locName = $chunk['locationName'];
echo $locName;
}
这是我遇到问题的部分,我无法看到任何结果?
foreach($obj['locations']['book'] as $chunk) {
$bkId = $chunk['bookId'];
echo $bkId;
}
那么你有什么尝试?你有什么困难呢? –
SO不是一个**免费编码资源**,我们**不按规范工作,甚至不是很好的**,您预计会为自己尝试一些东西。如果您在尝试编码时遇到特定问题,请提出问题,我们非常乐意帮助 – RiggsFolly
阅读[PHP手册的JSON页面](http://php.net/manual/en/ref .json.php) – RiggsFolly