如何告诉systemd启动的uWSGI守护进程使用特定的python？

我在网上的例子中拼凑了下面的uWSGI配置文件。（◠﹏◠）如何告诉systemd启动的uWSGI守护进程使用特定的python？

鉴于此配置 - 驻留在/etc/uwsgi.d/myapp.ini和被用于启动uwsgi守护进程，反过来，通过myappsystemd/systemctl - 这配置指令做我用它告诉使用特定的虚拟环境PYTHON for myapp？

是不是home =？

换句话说，当它调用django.wsgi应用程序时，我该如何告诉它（或它是如何知道的）：/home/myapp_unixHome/.virtualenvs/myapp/bin/python？

[uwsgi] 

# ======================================================= 
# Directories ... 
# ======================================================= 
home  = /home/myapp_unixHome/.virtualenvs/myapp/ <--- Python virtualenv dir. 
chdir  = /home/myapp_unixHome/myapp/    <--- Django App here. 
wsgi-file = /home/myapp_unixHome/myapp/django.wsgi <--- Including this django.wsgi file. 
static-map = /m=/home/myapp_unixHome/myapp/static/  <--- Static files. 
# ======================================================= 

# ======================================================= 
# TO BE NAMED ... 
# ======================================================= 
master = true 
processes = 5 
# ======================================================= 

# ======================================================= 
# myapp communicates w/ nginx via a UNIX domain socket. 
# ======================================================= 
socket  = /run/uwsgi/myapp.sock 
chmod-socket = 664 
uid   = nginx 
gid   = nginx 
vacuum  = true 
# ======================================================= 

# ======================================================= 
# uWSGI Log file. 
# ======================================================= 
logto = /var/log/uwsgi.log 
# =======================================================

谢谢。

来源

2017-10-06 prismalytics.io