我正在尝试编写通过UDP进行通信的tic-tack-toe游戏。 现在我有一些代码:从缓存中获取缓冲
int recv_txt(int sock, struct sockaddr_in *incoming_addr)
{
char bud[MAX_LENGTH];
unsigned int incoming_add_len;
incoming_add_len = sizeof(*incoming_addr);
if(recvfrom(sock, &buf, MAX_LENGTH, 0 (struct sockaddr*)incoming_addr, &incoming_addr_len) < 0)
{
return 0;
}
printf("received %s", buf);
return 1;
}
int main(int argv, char **argc)
{
/** some code to create socket etc */
struct sockaddr_in incoming_addr;
for(;;)
{
recv_txt(sock, &incoming_addr);
//here I would like to create new thread, which will process the buffer from recv_txt and send response;
}
}
,现在我需要从recv_txt
得到缓冲,把它里面的结构是这样的:
struct M_s
{
struct sockaddr_in address;
char[MAX_LENGTH] buffer;
}
,并把它传递给新的线程。但我无法从recv_txt
获得缓冲区。我很新的C,现在我不能使用指针非常好。
感谢您的任何建议。
编辑
我试图通过Frankie_c提供的解决方案,但我有问题,现在printf
。 当我尝试在main
:
LP_ARGS_STRUCT args = recv_txt(sock)
printf("data from: %s", inet_ntoa(args->address.sin_adrr))
我没有得到任何打印到控制台或遇到错误信息。
EDIT2 - 全码
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <string.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <arpa/inet.h>
#include <pthread.h>
#define SRV_PORT 23456
#define MAX_TXT_LENGTH 1000
#define MAX_ROOMS 1
int sock;
typedef struct args_s
{
struct sockaddr_in address;
char buffer[MAX_TXT_LENGTH];
} ARGS_STRUCT, *LP_ARGS_STRUCT;
//typedef struct args_s args;
LP_ARGS_STRUCT recv_txt(int sock)
{
LP_ARGS_STRUCT args = malloc(sizeof(ARGS_STRUCT));
//memory error
if(!args)
{
return 1;
}
unsigned int incoming_addr_len = sizeof(args->address);
//incoming_addr_len = sizeof(*incoming_addr);
if (recvfrom(sock, &args->buffer, MAX_TXT_LENGTH, 0,
(struct sockaddr*)&args->address, &incoming_addr_len) < 0)
{
free(args);
return NULL;
}
printf("received: %s %s\n", args->buffer, inet_ntoa(args->address.sin_addr));
return 1;
}
int main(int argv, char **argc)
{
int i = 0;
int optval;
struct sockaddr_in addr, incoming_addr;
char buffer[MAX_TXT_LENGTH];
/* create socket */
sock = socket(PF_INET, SOCK_DGRAM, IPPROTO_UDP);
if (sock < 0)
{
err("socket()");
}
/* set reusable flag */
optval = 1;
setsockopt(sock, SOL_SOCKET, SO_REUSEADDR, &optval, sizeof(optval));
/* prepare inet address */
memset(&addr, 0, sizeof(addr));
addr.sin_family = AF_INET;
addr.sin_port = htons(SRV_PORT);
addr.sin_addr.s_addr = htonl(INADDR_ANY); /* listen on all interfaces */
if (bind(sock, (struct sockaddr*)&addr, sizeof(addr)) < 0)
{
err("bind");
}
for(;;)
{
LP_ARGS_STRUCT args = recv_txt(sock);
if(!args) continue;
printf("%s\n", args->buffer);
}
return 0;
}
和接收数据包后,我得到:
received: Hello 192.168.56.1
Segmentation fault (code dumped)
Process returned 139 (0x8B)
您是否考虑过使用更高级别的语言编写此程序?你想要做的事情是可能的,但是你在极深的一端跳进了鲨鱼坦克。 – zwol
但是如何从'recv_txt'获得缓冲区,它接收到的缓冲区只是该函数的本地区域,您不会将其返回或复制到作为参数传递的缓冲区。 –
@zwol 我知道,但我没有选择。这是从学校项目和客户端这个游戏是用Java编写的,但服务器必须在C. – Sk1X1