如何将字符串转换为Apache HttpComponents HttpRequest

我有一个包含HTTP头的字符串。我想把它变成一个Apache HttpComponents HttpRequest对象。有没有办法做到这一点，而不是自己挑选字符串？如何将字符串转换为Apache HttpComponents HttpRequest

本教程：http://hc.apache.org/httpcomponents-core-dev/tutorial/html/fundamentals.html#d5e56和javadoc并没有多少指示。

来源

2012-03-26 Jason Thompson

一个类将字符串转换到Apache请求：

import org.apache.http.*; 
import org.apache.http.impl.DefaultHttpRequestFactory; 
import org.apache.http.impl.entity.EntityDeserializer; 
import org.apache.http.impl.entity.LaxContentLengthStrategy; 
import org.apache.http.impl.io.AbstractSessionInputBuffer; 
import org.apache.http.impl.io.HttpRequestParser; 
import org.apache.http.io.HttpMessageParser; 
import org.apache.http.io.SessionInputBuffer; 
import org.apache.http.message.BasicHttpEntityEnclosingRequest; 
import org.apache.http.message.BasicLineParser; 
import org.apache.http.params.BasicHttpParams; 

import java.io.ByteArrayInputStream; 
import java.io.IOException; 

/** 
* 
*/ 
public class ApacheRequestFactory { 
    public static HttpRequest create(final String requestAsString) { 
     try { 
      SessionInputBuffer inputBuffer = new AbstractSessionInputBuffer() { 
       { 
        init(new ByteArrayInputStream(requestAsString.getBytes()), 10, new BasicHttpParams()); 
       } 

       @Override 
       public boolean isDataAvailable(int timeout) throws IOException { 
        throw new RuntimeException("have to override but probably not even called"); 
       } 
      }; 
      HttpMessageParser parser = new HttpRequestParser(inputBuffer, new BasicLineParser(new ProtocolVersion("HTTP", 1, 1)), new DefaultHttpRequestFactory(), new BasicHttpParams()); 
      HttpMessage message = parser.parse(); 
      if (message instanceof BasicHttpEntityEnclosingRequest) { 
       BasicHttpEntityEnclosingRequest request = (BasicHttpEntityEnclosingRequest) message; 
       EntityDeserializer entityDeserializer = new EntityDeserializer(new LaxContentLengthStrategy()); 
       HttpEntity entity = entityDeserializer.deserialize(inputBuffer, message); 
       request.setEntity(entity); 
      } 
      return (HttpRequest) message; 
     } catch (IOException e) { 
      throw new RuntimeException(e); 
     } catch (HttpException e) { 
      throw new RuntimeException(e); 
     } 
    } 
}

并示出如何使用它的测试类：

import org.apache.http.HttpRequest; 
import org.apache.http.NameValuePair; 
import org.apache.http.client.utils.URLEncodedUtils; 
import org.apache.http.message.BasicHttpEntityEnclosingRequest; 
import org.junit.Test; 

import java.io.IOException; 
import java.net.URI; 
import java.util.List; 

import static org.junit.Assert.*; 

/** 
* 
*/ 
public class ApacheRequestFactoryTest { 
    @Test 
    public void testGet() { 
     String requestString = "GET /?one=aone&two=atwo HTTP/1.1\n" + 
       "Host: localhost:7788\n" + 
       "Connection: Keep-Alive\n" + 
       "User-Agent: Apache-HttpClient/4.0.1 (java 1.5)"; 

     HttpRequest request = ApacheRequestFactory.create(requestString); 
     assertEquals("GET", request.getRequestLine().getMethod()); 
     List<NameValuePair> pairs = URLEncodedUtils.parse(URI.create(request.getRequestLine().getUri()), "ISO-8859-1"); 
     checkPairs(pairs); 
    } 

    @Test 
    public void testPost() throws IOException { 
     String requestString = "POST/HTTP/1.1\n" + 
       "Content-Length: 17\n" + 
       "Content-Type: application/x-www-form-urlencoded; charset=ISO-8859-1\n" + 
       "Host: localhost:7788\n" + 
       "Connection: Keep-Alive\n" + 
       "User-Agent: Apache-HttpClient/4.0.1 (java 1.5)\n" + 
       "\n" + 
       "one=aone&two=atwo"; 

     HttpRequest request = ApacheRequestFactory.create(requestString); 
     assertEquals("POST", request.getRequestLine().getMethod()); 
     List<NameValuePair> pairs = URLEncodedUtils.parse(((BasicHttpEntityEnclosingRequest)request).getEntity()); 
     checkPairs(pairs); 
    } 

    private void checkPairs(List<NameValuePair> pairs) { 
     for (NameValuePair pair : pairs) { 
      if (pair.getName().equals("one")) assertEquals("aone", pair.getValue()); 
      else if (pair.getName().equals("two")) assertEquals("atwo", pair.getValue()); 
      else assertTrue("got more parameters than expected:"+pair.getName(), false); 
     } 
    } 
}

和一个小咆哮：

哪些APACHE HTTP团队思考？ api的使用非常尴尬。世界各地的开发人员正在浪费时间编写封装和转换类，以便每天使用该工厂的应用程序（例如，将字符串转换为apache http请求的简单操作，以及需要提取表单的奇怪方式参数（还必须以两种不同的方式完成，具体取决于所做的请求类型））。全球时间浪费了，因为这是巨大的。当你从底层开始写一个API时，从规格开始，你必须从顶层开始一个层（顶层是一个界面，你可以完成典型的工作，而不必理解或查看代码的实现方式），使每天使用图书馆方便和直观。 Apache的http库是什么，但。它是这种类型任务的标准库几乎是个奇迹。

来源

2012-05-14 10:49:29 user467257

如何将字符串转换为Apache HttpComponents HttpRequest

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