这是因为触发器运行的方式,基本上它不在您的查询执行窗口中。执行此操作的一种方法是登录到事件查看器。
Create trigger TestTrigger on
tablefortrigger
for insert
as
–Declare variable to hold message
Declare @Msg varchar(8000)
–Assign to message “Action/Table Name/Time Date/Fields inserted
set @Msg = ‘Inserted | tablefortrigger | ‘ + convert(varchar(20), getdate()) + ‘ | ‘
+(select convert(varchar(5), track)
+ ‘, ‘ + lastname + ‘, ‘ + firstname
from inserted)
–Raise Error to send to Event Viewer
raiserror(50005, 10, 1, @Msg)
这样做的另一种方式是写一个文件,还有当然是权限问题在这里,但你可以这样做:
Alter trigger TestTrigger on
tablefortrigger
for insert
as
Declare @Msg varchar(1000)
–Will hold the command to be executed by xp_cmdshell
Declare @CmdString varchar (2000)
set @Msg = ‘Inserted | tablefortrigger | ‘ + convert(varchar(20), getdate()) + ‘ — ‘
+(select convert(varchar(5), track)
+ ‘, ‘ + lastname + ‘, ‘ + firstname
from inserted)
–Raise Error to send to Event Viewer
raiserror(50005, 10, 1, @Msg)
set @CmdString = ‘echo ‘ + @Msg + ‘ >> C:logtest.log’
–write to text file
exec master.dbo.xp_cmdshell @CmdString
更多信息可以在这里找到:http://www.sql-server-performance.com/2005/log-file-trigger/