MySQL单个查询可能吗？

Question

我有一个MySQL声明：

SELECT name, ((AVG (q1) + AVG(q2) + AVG(q3)/3) AS Average 
FROM tresults GROUP BY name ORDER BY name; 

我也有另一个MySQL statment：

SELECT name, ((AVG (q1) + AVG(q2) + AVG(q3)/3) AS Average 
FROM tresults WHERE q35 = 1 GROUP BY name ORDER BY name; 

我使用子查询的尝试，但因为它返回多行下面的代码无法正常工作：

SELECT name, ((AVG (q1) + AVG(q2) + AVG(q3)/3) AS Average, 
    (SELECT ((AVG (q1) + AVG(q2) + AVG(q3)/3) 
    FROM tresults WHERE q35 = 1 GROUP BY name ORDER BY name) AS Average2 
FROM tresults GROUP BY name ORDER BY name; 

是否可能以及该语句的结构是什么样子？

在此先感谢您的任何反馈意见和建议。

Answer 1

SELECT name, 
     (AVG (AVG (q1) + AVG(q2) + AVG(q3)/3) AS Average, 
     (AVG (AVG (case when q35 = 1 then q1 else 0 end) + 
      (AVG (case when q35 = 1 then q2 else 0 end) + 
      (AVG (case when q35 = 1 then q3 else 0 end)/3) AS q35_Average 
FROM tresults 
GROUP BY name 
ORDER BY name 

Answer 2

因为你计算平均值的平均水平，这可能是更快地使用sum而不是使用avg功能

select name, 
    sum(q1+q2+q3)/sum(3) as average 
    sum(case when q35 = 1 then (q1+q2+q3) else 0 end) 
    /sum(case when q35 = 1 then 3 else 0 end) as q35_average 
from tresults 
group by name 
order by name