我有一个名为表:工人和一个名为表:以下格式时间表:mysql的两个返回的最小值
工人:
| id | name | vacationA | vacationB | workhistory |
| 1 | Florin | 2017-05-05 | 2017-05-25 | 2010-01-01 |
| 2 | Andrei | 2017-06-05 | 2017-06-25 | 2010-01-01 |
| 3 | Alexandra | 2017-07-05 | 2017-07-25 | 2010-01-01 |
| 4 | Emilia | 2017-08-05 | 2017-08-25 | 2010-01-01 |
| 5 | Nicoleta | 2017-09-05 | 2017-09-25 | 2010-01-01 |
+----+-----------+------------+------------+-------------+
时间表:
| day | month | name | shifts |
+-----+-------+-----------+--------+
| 1 | 6 | Florin | 0 |
| 1 | 6 | Andrei | 1 |
| 1 | 6 | Alexandra | 2 |
| 1 | 6 | Emilia | 3 |
| 1 | 6 | Nicoleta | 4 |
+-----+-------+-----------+--------+
我需要询问桌上的“工作人员”给我2个随机姓名,最少轮班人数,工人不应处于休假期。工作经历也必须超过18个月。 在这种情况下,我需要的查询应该返回Florin和Andrei。
这是我这么远,但认为它不工作:
SELECT name FROM workers WHERE (CURDATE() NOT BETWEEN vacationA AND vacationB) AND workhistory > (DATE_SUB(CURDATE(), INTERVAL 18 MONTH)) AND name IN (SELECT name FROM schedule ORDER BY shifts LIMIT 2) ORDER BY RAND() LIMIT 2;
该查询返回 1235 - This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'
。
谢谢!
谢谢您的回答。我已经更新了这个问题,如果你能帮忙的话。 – Kellog