mysql查询 - 显示使用内部连接的mysql结果的错误

Question

我有2个表，我想合并。我想用相应的总量和总量打印所有产品。

这就是我所拥有的。

//Product Table 
productID productName 
    1    A 
    2    B 
    3    C 


//Order Record (This came from 2 tables that I have successfully merged) 
orderID  productID  quantity  amount 
    1   1    5   100 
    2   2    2   50 
    3   2    3   150    

我想这样做

productID  productName  totalQuantity  totalAmount 
    1    A     8    250 
    2    B     2    50 
    3    C     0    0  
//instead of 0 for total Quantity and total Amount, it shows 2 and 50 respectively. 

这是我的PHP代码。它能够正确输出前两行（产品A和B）的数据，但是当涉及到最后一行（产品C）时，它会复制产品B的数据。请告诉我我的代码中有什么问题？先谢谢你。

$products = $wpdb->get_results("SELECT * FROM wp_products"); 

foreach($products as $product){ 
    $productID = $product->productID; 
    $productName = $product->productName; 

    $orders = $wpdb->get_results("SELECT a.productID, SUM(a.quantity) as totalQuantity, SUM(a.amount) as totalSales FROM a INNER JOIN b ON a.orderID = b.orderID GROUP BY productID"); 

    if(is_null($orders)){ 
     $totalQuantity = 0; 
     $totalSales = '0.00'; 
    } 

    foreach($orders as $order){ 
     $totalQuantity = $order->totalQuantity; 
     $totalSales = $order->totalSales; 
    } 

    $orderItem = array(
         'productID' => $productID, 
         'productName' => $productName, 
         'totalQuantity' => $totalQuantity, 
         'totalSales' => $totalSales 
        ); 
       $records[] = $orderItem; 
} 

Answer 1

我不相信你的查询是正确的。

我没有看到表名。尝试将其更改为：

FROM `tablename` AS a INNER JOIN `othertable` AS b 

使用表a和b的名称替换表名和其他表。

Answer 2

快速的修复（刚加入WHERE到您的查询）：

$orders = $wpdb->get_results("SELECT 
     a.productID, 
     SUM(a.quantity) as totalQuantity, 
     SUM(a.amount) as totalSales 
     FROM a 
     INNER JOIN b 
     ON a.orderID = b.orderID 
     WHERE a.productID = $productID 
     GROUP BY productID"); 

但看你的片段，我相信你可以把它简化（代替全片段）到：

$records = $wpdb->get_results("SELECT 
     p.productID, 
     p.productName, 
     COALESCE(SUM(a.quantity),0) as totalQuantity, 
     COALESCE(SUM(a.amount),0) as totalSales 
    FROM wp_products p 
    LEFT JOIN a 
    GROUP BY p.productID");