如果因闰年(2月29日)而知道年份,则只能添加一天。
如果当年是当年,以下解决方案应该做的工作:
对于 “SA25MAY”:
try {
String str_date = "SA25MAY";
// remove SA
str_date = str_date.replaceFirst("..", "");
// add current year
Calendar c = Calendar.getInstance();
str_date = c.get(Calendar.YEAR) + str_date;
// parse date
Date date;
SimpleDateFormat formatter = new SimpleDateFormat("yyyyddMMM");
date = formatter.parse(str_date);
System.out.println("Today is " + date);
// add day
c.setTime(date);
c.add(Calendar.DATE, 1);
// rebuild the old pattern with the new date
SimpleDateFormat formatter2 = new SimpleDateFormat("EEEddMMM");
String tomorrow = formatter2.format(c.getTime());
tomorrow = tomorrow.toUpperCase();
tomorrow = tomorrow.substring(0, 2) + tomorrow.substring(3);
System.out.println("Tomorrow is " + tomorrow);
} catch (Exception e) {
e.printStackTrace();
}
或为 “SA-25-MAY”:
try {
String str_date = "SA-25-MAY";
// remove SA
str_date = str_date.replaceFirst("..-", "");
// add current year
Calendar c = Calendar.getInstance();
str_date = c.get(Calendar.YEAR) + "-" + str_date;
// parse date
Date date;
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-dd-MMM");
date = formatter.parse(str_date);
System.out.println("Today is " + date);
// add day
c.setTime(date);
c.add(Calendar.DATE, 1);
// rebuild the old pattern with the new date
SimpleDateFormat formatter2 = new SimpleDateFormat("EEE-dd-MMM");
String tomorrow = formatter2.format(c.getTime());
tomorrow = tomorrow.toUpperCase();
tomorrow = tomorrow.substring(0, 2) + tomorrow.substring(3);
System.out.println("Tomorrow is " + tomorrow);
} catch (Exception e) {
e.printStackTrace();
}
['SimpleDateFormat'](http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html)是你正在寻找的。 – sp00m
我收到像“SA25MAY”(Saturday25MAY)这样的输入,我不知道如何将它转换为日期时间变量 –
请提供刚刚在您的问题中尝试的代码片段。 – sp00m