对满足两个单独标准的人员的查询

我需要找到一种方法来计算居住在同一家中并且投票了“DEMO”，“REP”或“DEMO-REP”的选民人数。我已经得到这个目前为止，http://sqlfiddle.com/#!3/469d4/3 对满足两个单独标准的人员的查询

例如，英里和Raquel住在同一个房子，并且都投了'REP'，他们将被计入'REP'列。克里斯和塔尼亚都住在同一栋房子里，并投了'REP'和'DEMO'，所以他们将进入'DEMO-REP'专栏。小提琴结果需要。

1 http://img824.imageshack.us/img824/3305/resultbx.png

在此先感谢

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2012-07-23 user973671

不知道我理解。看起来你有来自7个不同家庭的11票，但只占4个。你是否不想只返回一次投票结果？ – 2012-07-23 16:19:22

是的，在真正的查询中，我想要返回只投一次的家庭的结果，我只是将这部分留给了这个问题。谢谢 – user973671 2012-07-23 16:36:41

我想这你想要做什么：

select sum(votes) as total, sum(demo*(1-rep)) as demoonly, 
     sum(rep*(1-demo)) as reponly, sum(demo*rep) as demorep 
from (select address, cont(*) as votes, 
      max(case when voted = 'DEMO' then 1 else 0 end) as demo, 
      max(case when voted = 'REP' then 1 else 0 end) as rep 
     from t 
     group by address 
    ) t

假设你想户（地址）与一个以上的人：

select sum(votes) as total, sum(demo*(1-rep)) as demoonly, 
     sum(rep*(1-demo)) as reponly, sum(demo*rep) as demorep 
from (select address, count(*) as votes, 
      max(case when voted = 'DEMO' then 1 else 0 end) as demo, 
      max(case when voted = 'REP' then 1 else 0 end) as rep 
     from test4 
     group by address 
     having count(distinct name) > 1 
    ) t

在这里，我假设“地址”是家庭的代理人，因为数据中没有家庭字段。

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2012-07-23 16:20:59

我不认为这会给出正确的结果，我让它在小提琴上工作，http://sqlfiddle.com/#!3/469d4/23。谢谢 – user973671 2012-07-23 16:42:51

您是否修复了查询？我想你在我回答后澄清了这个问题。 – 2012-07-23 17:23:12

不，它仍然是不固定的，谢谢 – user973671 2012-07-23 21:49:08

编辑：这适用于您的SQL小提琴代码。

我会这样：

SELECT COUNT(Voted) AS TOTAL, 
(
SELECT COUNT(DISTINCT address) FROM test4 
WHERE address NOT IN (SELECT address FROM test4 WHERE Voted = 'REP') 
) AS Demo, 
(SELECT COUNT(DISTINCT address) FROM test4 
WHERE address NOT IN (SELECT address FROM test4 WHERE Voted = 'DEMO') 
) AS Rep, 
(SELECT COUNT(DISTINCT address) FROM test4 
WHERE address IN (SELECT address FROM test4 WHERE Voted = 'REP') AND address IN (SELECT address FROM test4 WHERE Voted = 'DEMO') 
) AS DemoRep 
    FROM test4

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2012-07-23 16:38:30 ristonj

不幸的是，表中没有HouseholdID，谢谢 – user973671 2012-07-23 16:54:30

如果您将“Address”替换为“HouseholdID”，它应该也能正常工作。 – ristonj 2012-07-23 19:52:18

对不起，我觉得有些困惑，如果地址匹配，那么家庭应该被视为一个家庭，唯一的家庭应该出现在结果中。谢谢 – user973671 2012-07-23 22:03:09

对满足两个单独标准的人员的查询

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