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我有以下的数据库表:的CakePHP中可容纳的行为未正常工作
products
********
id
title
artist_id
artists
*******
id
profile
rating
person_id
people
******
id
full_name
以下模型协会:
Product Model
*************
public $belongsTo = array(
'Artist' => array(
'className' => 'Artist'
'foreignKey' => 'artist_id'
)
);
Artist Model
************
public $belongsTo = array(
'Person' => array(
'className' => 'Person'
'foreignKey' => 'person_id'
)
);
public $hasMany = array(
'Product' => array(
'className' => 'Product'
'foreignKey' => 'product_id'
)
);
Person Model
************
public $hasOne = array(
'Artist' => array(
'className' => 'Artist'
'foreignKey' => 'person_id'
)
);
我已经设置这三个模型的使用中可容纳的行为使用:
public $actsAs = array('Containable');
当我使用以下来获得产品的细节随着艺术IST的名字:
$this->Product->find('first', array('conditions' => array('Product.id' => $id), 'contain' => 'Person.full_name'))
我得到警告:
Model "Product" is not associated with model "Person"
,我只拿到产品的详细信息,即没有艺术家的名字。这是为什么发生?