2015-02-06 71 views
1

下面的代码定义了一个用于转换字段值的字典。数据被读取,一些值基于这个字典被转换,并被写入到一个表中。它按原样工作。这个问题,我现在想将这个配置移到.py文件之外的一个JSON配置文件中。如何使这个实体序列化/反序列化?

lookups = { 
    11: { 
     "ST1": ["ABC"], 
     "UNK01": ["125", "ACD"], 
     "A": ["52"], 
     "B": ["91"], 
     "C": ["92"], 
     "D": ["95"] 
     }, 
    10: { 
     "XYZ01": ["91"], 
     "XYZ02": ["83"], 
     "XYZ03": ["27"] 
     } 
} 

根据jsonlint.com,为了上述值被分配给lookups是有效的JSON,我必须报1110密钥。这样做会破坏我的Python代码并显示TypeError: list indices must be integers, not str

如何创建有效的JSON并尽量减少对代码的更改?

回答

0

如果你知道你的钥匙是什么类型的数据,在按键上简单int就足够了:

dictionary_from_json = json.loads(dumped) 
newdict = {} 
for key, val in dictionary_from_json: 
    newdict[int(key)] = val 
1

如果你想将它转储到JSON文件:

import json 

with open("config.json","w") as f: 
    json.dump(lookups, f) # dump dict to file 

with open("config.json") as f: 
    s = json.load(f) # load dict from file 
print(s) 
{'11': {'ST1': ['ABC'], 'A': ['52'], 'D': ['95'], 'UNK01': ['125', 'ACD'], 'B': ['91'], 'C': ['92']}, '10': {'XYZ01': ['91'], 'XYZ03': ['27'], 'XYZ02': ['83']}} 

如果您需要密钥作为整数,您可以循环并投射为整数或使用pickle

import pickle 
with open("in.pkl","wb") as f: 
    pickle.dump(lookups, f) 

with open("in.pkl","rb") as f: 
    s = pickle.load(f) 
print(s) 
{10: {'XYZ03': ['27'], 'XYZ01': ['91'], 'XYZ02': ['83']}, 11: {'UNK01': ['125', 'ACD'], 'B': ['91'], 'D': ['95'], 'ST1': ['ABC'], 'C': ['92'], 'A': ['52']}} 

如果不是按原样使用。

0

您可以扩展json.decoder并在可能的情况下将所有的键转换为int。

import json 
class Json(json.JSONDecoder): 
    def decode(self,json_string): 
     default_obj = super(Json,self).decode(json_string) 
     new_obj = self._rec_serial(default_obj) 
     return new_obj 

    def _rec_serial(self,default): 
     new_dict = {} 
     for key,value in default.items(): 
      is_dict = isinstance(value,dict) 
      value = self._rec_serial(value) if is_dict else value 
      try: 
       new_dict[int(key)] = value 
      except ValueError: 
       new_dict[key] = value 
     return new_dict 

json2= Json() 
d = json2.decode(dumped) 
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