Java中，尝试捕获后继续

Question

当我运行程序100是由数字众说纷纭，但一旦它到达0将出现一条消息，告诉用户说100不能由0

分我如何获得程序在错误之后继续，并将其余的数字除以100。

这是我当前的代码：

public class testing { 
    int[] table; 
    int number; 

    public testing(int number) { 
     this.number = number; 
     table = new int[number]; 
    } 

    public static void main(String[] args) { 
     try { 
      int[] numbers = { 2, 3, 0, 4, 5 }; 
      testing division; 
      for (int i = 0; i < 5; i++) { 
       division = new testing(100/numbers[i]); 
       System.out.println("Answer is " + division.number); 
      } 
     } catch (Exception e) { 
      System.out.println("A number cannot be divided by 0"); 
     } 
    } 
} 

Answer 1

你可以简单地做出更细粒度的规模try/catch语句 - 把它内 for循环。

for (int i = 0; i < 5; i++) { 
    try { 
     division = new testing(100/numbers[i]); 
     System.out.println("Answer is " + division.number); 
    } catch (ArithmeticException e) { // avoid catching with the overly broad Exception 
     System.out.println("A number cannot be divided by 0"); 
    } 
} 

我想尽量让我的例外更具体，避免捕捉使用过度广泛的Exception类，这里使用ArithmeticException。

但更重要的是，我完全摆脱了try catch，并简单地测试了0，完全避免了异常。

for (int i = 0; i < 5; i++) { 
    if (numbers[i] == 0) { 
     System.out.println("A number cannot be divided by 0"); 
    } else { 
     division = new testing(100/numbers[i]); 
     System.out.println("Answer is " + division.number); 
    } 
} 

Answer 2

看跌的try-catch中的内：

for (int i = 0; i < 5; i++) { 
    try{ 
    division = new testing(100/numbers[i]); 
    System.out.println("Answer is " + division.number); 
    } catch(Exception e){ 
     System.out.println("A number cannot be divided by 0"); 
    } 
    } 

Answer 3

更新代码：增加了一个尝试捕捉你的代码：

public class testing { 

    int[] table; 
    int number; 

    public testing(int number) { 
    this.number = number; 
    table = new int[number]; 
    } 

    public static void main(String[] args) { 
    int[] numbers = { 2, 3, 0, 4, 5 }; 
    testing division; 

    for (int i = 0; i < 5; i++) { 
     try { 
     division = new testing(100/numbers[i]); 
     System.out.println("Answer is " + division.number); 
     } catch (Exception e) { 
     System.out.println("A number cannot be divided by 0"); 
     } 
    } 
    } 
} 

Answer 4

，如果出现异常，也没有办法去回来，但我们可以处理异常并与下一次迭代一起进行，或者在分割之前的条件下添加以下内容：

**if(numbers[i] != 0){** 
division = new testing(100/numbers[i]); 

或把try try catch在循环中。