在awk中对数组进行排序

Question

如何在awk中对数组进行排序？考虑 “sortNum.awk”：

{ 
    split($0,a," ") 
    for (i in a) print a[i] 
    print "####" 
    asort(a) 
    for (i in a) print a[i] 
} 

与echo "4 3 2 1" | awk -f sortNum.awk运行提供了

1 
4 
3 
2 
#### 
4 
1 
2 
3 

我使用了GNU AWK版本3.1.8。

Answer 1

for (i in a)不选择数字顺序索引，你需要做的是明确的。

{ 
    n = split($0,a," "); 
    for (i = 1; i <= n; i++) print a[i]; 
    print "####" 
    asort(a) 
    for (i = 1; i <= n; i++) print a[i]; 
}