如何删除/删除标题中的wordpress feed url？

Question

如何删除/删除wordpress feed来自head标签的网址header.php？

例以下网址：

<link rel="alternate" type="application/rss+xml" title="Example Business &raquo; Feed" href="http://example.com/feed/"/> 
<link rel="alternate" type="application/rss+xml" title="Example Business &raquo; Comments Feed" href="http://example.com/comments/feed/"/> 
<link rel="alternate" type="application/rss+xml" title="Example Business &raquo; Home Page Live Comments Feed" href="http://example.com/home/feed/"/> 

我不希望使用任何插件一样。

Answer 1

我最近有需要删除Feed url链接元素，并试图避免自定义核心WordPress函数以下解决方案的作品。

确保您的主题目录中有一个functions.php文件。如果不创建该文件并编辑该文件。以下几行将有助于从wp_head()函数中删除选择行：

<?php 
remove_action('wp_head', 'feed_links_extra', 3); // Display the links to the extra feeds such as category feeds 
remove_action('wp_head', 'feed_links', 2); // Display the links to the general feeds: Post and Comment Feed 
remove_action('wp_head', 'rsd_link'); // Display the link to the Really Simple Discovery service endpoint, EditURI link 
remove_action('wp_head', 'wlwmanifest_link'); // Display the link to the Windows Live Writer manifest file. 
remove_action('wp_head', 'index_rel_link'); // index link 
remove_action('wp_head', 'parent_post_rel_link', 10, 0); // prev link 
remove_action('wp_head', 'start_post_rel_link', 10, 0); // start link 
remove_action('wp_head', 'adjacent_posts_rel_link', 10, 0); // Display relational links for the posts adjacent to the current post. 
remove_action('wp_head', 'wp_generator'); // Display the XHTML generator that is generated on the wp_head hook, WP version 
?>