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我的问题是,我似乎无法获得我需要的节点列表。我尝试了多种解决方案,但似乎并不奏效。这是我的xml文件的一部分:在XML中找不到某个节点
<findItemsByCategoryResponse xmlns="http://www.ebay.com/marketplace/search/v1/services">
<ack>Success</ack>
<version>1.13.0</version>
<timestamp>2016-08-23T07:33:22.497Z</timestamp>
<searchResult count="100">
<item>
<itemId>152210133431</itemId>
<title>...</title>
<globalId>EBAY-GB</globalId>
<primaryCategory>
<categoryId>218</categoryId>
<categoryName>Magic the Gathering</categoryName>
</primaryCategory>
<galleryURL>
http://thumbs4.ebaystatic.com/m/meIDrVqhmbpQMYCxzeUvR9Q/140.jpg
</galleryURL>
<viewItemURL>
http://www.ebay.co.uk/itm/MTG-See-Unwritten-Khans-Tarkir-MYTHIC-MINT-/152210133431
</viewItemURL>
<paymentMethod>PayPal</paymentMethod>
<autoPay>false</autoPay>
<location>London,United Kingdom</location>
<country>GB</country>
<shippingInfo>
<shippingServiceCost currencyId="GBP">1.1</shippingServiceCost>
<shippingType>Flat</shippingType>
<shipToLocations>GB</shipToLocations>
</shippingInfo>
<sellingStatus>
<currentPrice currencyId="GBP">0.5</currentPrice>
<convertedCurrentPrice currencyId="GBP">0.5</convertedCurrentPrice>
<bidCount>0</bidCount>
<sellingState>Active</sellingState>
<timeLeft>P0DT0H19M12S</timeLeft>
</sellingStatus>
<listingInfo>
<bestOfferEnabled>false</bestOfferEnabled>
<buyItNowAvailable>false</buyItNowAvailable>
<startTime>2016-08-18T07:52:34.000Z</startTime>
<endTime>2016-08-23T07:52:34.000Z</endTime>
<listingType>Auction</listingType>
<gift>false</gift>
</listingInfo>
<condition>
<conditionId>1000</conditionId>
<conditionDisplayName>New</conditionDisplayName>
</condition>
<isMultiVariationListing>false</isMultiVariationListing>
<topRatedListing>false</topRatedListing>
</item>
</searchResult>
<paginationOutput>...</paginationOutput>
<itemSearchURL>...</itemSearchURL>
</findItemsByCategoryResponse>
通常有这xml文件100个节点,我只是短的文件。我试图在XmlNodeList中获取''item''节点和一切内容,但是当我调试它时说它包含0个项目。在此之后,我想要检索一些数据,如代码中所示。注意:我尝试了很多xpath值! 这里是我使用的代码:
XmlDocument xmlText = new XmlDocument();
xmlText.Load(basicUrl);
XmlElement root = xmlText.DocumentElement;
XmlNodeList xnList = root.SelectNodes("//item");
foreach(XmlNode item in xnList)
{
string title = item["title"].InnerText;
Console.WriteLine(title);
}
如何解释_why_这将/能够帮助? –
不太明白,它似乎不起作用,你能给我多一点信息?或者可能用linq而不是Xpath来搜索它? – Wouter
Xpath是一种在XML中进行搜索的非常好的方法我编辑了我的答案(我使用问题中提供的xml测试了代码) –