获得总笔数的总和PostgreSQL的

Question

的表是：

Orders 
----------- 
user_id 
state 


Items 
----------- 
order_id 
product_id 
total 

Products 
---------- 
user_id 


Users 
--------- 
name 
email 

关系如下：

User 
has_many :products 

Order 
has_many :items 
belongs_to :users 

Product 
has_many :items 
belongs_to :user 

Item 
belongs_to :items 

我想每个拥有该产品的用户items.total的总和

我目前有以下SQL语句：

SELECT *, SUM(items.total) as totalprice 
FROM "orders" 
INNER JOIN "items" ON "items"."order_id" = "orders"."id" 
INNER JOIN "products" ON "products"."id" = "items"."product_id" 
INNER JOIN "users" ON "users"."id" = "products"."user_id" 
WHERE "orders"."state" = 'complete' 
GROUP BY users.id 

OR

Order.complete.joins(:items => {:product => :user}).select("*, SUM(items.total) as totalprice").group('users.id') 

以上不起作用。我觉得这应该很容易。

Answer 1

在按查询分组中，您需要包含未在group by子句中汇总的所有列。如果更改查询到这一点，你可能有更好的运气

SELECT users.id, SUM(items.total) as totalprice 
FROM "orders" 
INNER JOIN "items" ON "items"."order_id" = "orders"."id" 
INNER JOIN "products" ON "products"."id" = "items"."product_id" 
INNER JOIN "users" ON "users"."id" = "products"."user_id" 
WHERE "orders"."state" = 'complete' 
GROUP BY users.id 

如果你想在输出更多的列，一行