我有以下代码(你不需要知道太多的查询来获取我的问题):获取同一列两次,不同的价值
if ($stmt = $cxn->prepare('SELECT p.post_id, p.reply_to, p.parent_id, p.post_path, p.user_id, p.content, p.datetime, p.total_likes, p.total_replies, p.total_reposts, l.like_id, l.user_id, u.username, u.display_name
FROM posts p
LEFT JOIN users u ON p.user_id = u.user_id
LEFT JOIN likes l ON l.post_id = p.post_id
WHERE l.user_id IN
(SELECT user_id FROM likes WHERE user_id IN
(SELECT following_id FROM follows WHERE user_id = ? AND following_id != ?))
AND l.user_id != p.user_id AND p.removed != 1
ORDER BY p.datetime DESC LIMIT 26')) {
$stmt->bind_param('ii', $id, $id);
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($post_id, $reply_to, $parent_id, $post_path, $user_id, $content, $datetime, $total_likes, $total_replies, $total_reposts, $like_id, $like_user_id, $username, $display_name);
}
现在,我有l.user_id
值是用户的整数值。
我怎么会到这个查询,这样我可以从users
表中获取的l.user_id
的用户名时,我已经查询u.username
为p.user_id
?
谢谢!
只需将该字段添加到查询中?我想我不了解你的问题。 –
@MikeBrant我已经为'p.user_id'获得'u.username'。我也想获得'l.user_id'的用户名。怎么样? – Walter
只需将'l.username'添加到您的查询中即可。 –