如何在隐藏后重新显示QDialog？

Question

我正在使用python和pyqt。我有一个我想暂时隐藏的对话框。调用

dlg.hide() 

后，我尝试调用

dlg.show() 

但没有任何反应。它永远不会重新显示。

我是pyqt的新手，非常感谢您的帮助。

在此先感谢。

Answer 1

您正在寻找exec_方法，使对话模式，了解其工作原理：

#!/usr/bin/env python 
#-*- coding:utf-8 -*- 

from PyQt4 import QtCore, QtGui 

class myDialog(QtGui.QDialog): 
    def __init__(self, parent=None): 
     super(myDialog, self).__init__(parent) 

     self.dialog = None 

     self.buttonShow = QtGui.QPushButton(self) 
     self.buttonShow.setText("Show Dialog") 
     self.buttonShow.clicked.connect(self.on_buttonShow_clicked) 

     self.buttonHide = QtGui.QPushButton(self) 
     self.buttonHide.setText("Close") 
     self.buttonHide.clicked.connect(self.on_buttonHide_clicked) 

     self.layout = QtGui.QVBoxLayout(self) 
     self.layout.addWidget(self.buttonShow) 
     self.layout.addWidget(self.buttonHide) 

    @QtCore.pyqtSlot() 
    def on_buttonHide_clicked(self): 
     self.accept() 

    @QtCore.pyqtSlot() 
    def on_buttonShow_clicked(self): 
     self.dialog = myDialog(self) 
     self.dialog.exec_() 

class myWindow(QtGui.QWidget): 
    def __init__(self, parent=None): 
     super(myWindow, self).__init__(parent) 

     self.buttonShow = QtGui.QPushButton(self) 
     self.buttonShow.setText("Show Dialog") 
     self.buttonShow.clicked.connect(self.on_buttonShow_clicked) 

     self.layout = QtGui.QVBoxLayout(self) 
     self.layout.addWidget(self.buttonShow) 

     self.dialog = myDialog(self) 

    @QtCore.pyqtSlot() 
    def on_buttonHide_clicked(self): 
     self.dialog.accept() 

    @QtCore.pyqtSlot() 
    def on_buttonShow_clicked(self): 
     self.dialog.exec_() 

if __name__ == "__main__": 
    import sys 

    app = QtGui.QApplication(sys.argv) 
    app.setApplicationName('myWindow') 

    main = myWindow() 
    main.show() 

    sys.exit(app.exec_())