我需要对一年的练习进行暴力破解。编译器不断抛出此错误:C++:整数常量对于其类型来说太大
bruteforceJS12.cpp:8:28: warning: integer constant is too large for its type [enabled by default]
我的代码是:
#include <iostream>
using namespace std;
int main(){
unsigned long long year(0);
unsigned long long result(318338237039211050000);
unsigned long long pass(1337);
while (pass != result)
{
for (unsigned long long i = 1; i<= year; i++)
{
pass += year * i * year;
}
cout << "pass not cracked with year = " << year << endl;
++year;
}
cout << "pass cracked with year = " << year << endl;
}
请注意,我已经与unsigned long long result(318338237039211050000ULL);
我使用gcc版本4.8.1
编辑试图:
这是使用InfInt库012的更正版本
#include <iostream>
#include "InfInt.h"
using namespace std;
int main(){
InfInt year = "113";
InfInt result = "318338237039211050000";
InfInt pass= "1337";
while (pass != result)
{
for (InfInt i = 1; i<= year; i++)
{
pass += year * i * year;
}
cout << "year = " << year << " pass = " << pass << endl;
++year;
}
cout << "pass cracked with year = " << year << endl;
}
您应该使用ASCII表示法。 –
使用'unsigned long long result = 318338237039211050000ULL;'失败吗?它可能只是它不喜欢这种初始化方法? –
@ScottMermelstein:文字后缀不适用于* that *目的。如果存在这样的类型,则整型文字已具有可表示它的类型。 –