在JBoss 6.1 Final中部署Jersey 1.11 REST风格的Web服务（RestEasy已经部署）

Question

对不起，我想要彻底，以免浪费你的时间，种类StackOverflow-ers。 :-)

由于JBoss使用Tomcat作为组件，我已经在Tomcat 7中成功地部署和测试了一个RESTful Web服务作为war文件，我（错误地）认为部署会像放下war文件一样简单进入我的JBoss 6.1服务器/默认/部署目录，不！起初，我得到一个错误，表示只允许一个JAX-RS应用程序类，这可以通过从部署者/目录中删除部署者/目录（所有，默认和标准服务器中的resteasy.deployer）来完成。

现在的关键是，我的Jboss启动过程中得到以下信息：

    10:38:07,431 INFO [PackagesResourceConfig] Scanning for root resource and provider classes in the packages: 
    net.ussouth.incomm.SPIL.resource 
    10:38:07,486 INFO [WebApplicationImpl] Initiating Jersey application, version 'Jersey: 1.11 12/09/2011 10:27 AM' 
    10:38:07,718 SEVERE [RootResourceUriRules] The ResourceConfig instance does not contain any root resource classes. 
    10:38:07,719 ERROR [[/SPIL]] StandardWrapper.Throwable: com.sun.jersey.api.container.ContainerException: The ResourceConfig instance does not contain any root resource classes. 
     at com.sun.jersey.server.impl.application.RootResourceUriRules.(RootResourceUriRules.java:99) [:1.11] 
     at com.sun.jersey.server.impl.application.WebApplicationImpl._initiate(WebApplicationImpl.java:1298) [:1.11] 
     at com.sun.jersey.server.impl.application.WebApplicationImpl.access$700(WebApplicationImpl.java:169) [:1.11] 
     at com.sun.jersey.server.impl.application.WebApplicationImpl$13.f(WebApplicationImpl.java:775) [:1.11] 
     at com.sun.jersey.server.impl.application.WebApplicationImpl$13.f(WebApplicationImpl.java:771) [:1.11] 

以下是资源类，这是WEB-INF/classes目录下：

    package net.ussouth.incomm.SPIL.resource; 

    import javax.ws.rs.Path; 
    import javax.ws.rs.POST; 
    import javax.ws.rs.Consumes; 
    import javax.ws.rs.core.MediaType; 
    import javax.ws.rs.Produces; 
    import javax.ws.rs.FormParam; 

    import org.apache.log4j.Logger; 

    @Path("/message") 
    public class MessageResource { 
     private static Logger log = Logger.getLogger(MessageResource.class); 


     @POST 
     @Path("/Search") 
     @Produces(MediaType.APPLICATION_XML) 
     @Consumes(MediaType.APPLICATION_FORM_URLENCODED) 
     public String search(@FormParam("message") String _msgToProvider, @FormParam("provider") String _provData) { 
     log.info("MesageResource.search method called"); 
     String outVal = null; 

     try{ 
      ProviderHandler hnd = new ProviderHandler(); 
      outVal = hnd.getOffers(_msgToProvider); 

     } catch(JAXBException ex) { 
      ... 
     } catch (SearchException ex) { 
      ... 
     } 

     return outVal; 
     }  
    } 

这里的web.xml文件：

<?xml version="1.0" encoding="UTF-8"?> 
<web-app 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns="http://java.sun.com/xml/ns/javaee" 
    xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
    id="WebApp_ID" 
    version="2.5"> 

    <display-name>Spil</display-name> 
    <welcome-file-list> 
    <welcome-file>index.html</welcome-file> 
    </welcome-file-list> 

    <servlet> 
    <servlet-name>SpilMessageService</servlet-name> 
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class> 

    <init-param> 
     <param-name>com.sun.jersey.config.property.packages</param-name> 
     <param-value>net.ussouth.incomm.SPIL.resource</param-value> 
    </init-param> 

    <init-param> 
     <param-name>log4j-properties-location</param-name> 
     <param-value>classes/log4j.xml</param-value> 
    </init-param> 

    <load-on-startup>1</load-on-startup> 
    </servlet> 
    <servlet-mapping> 
    <servlet-name>SpilMessageService</servlet-name> 
    <url-pattern>/*</url-pattern> 
    </servlet-mapping> 

</web-app> 

最后，良好的措施，这里的的jboss-web.xml中：

<?xml version="1.0" encoding="UTF-8"?> 
<!DOCTYPE jboss-web PUBLIC "-//JBoss//DTD Web Application 2.4//EN" "http://www.jboss.org/j2ee/dtd/jboss-web_4_2.dtd"> 
<jboss-web> 
    <context-root>SPIL</context-root> 
</jboss-web> 

谢谢你的帮助。我花了1.5天的时间研究并将我的头撞在墙上。

Answer 1

脓疱

我跟你遇到了同样的问题（新泽西州1.11 + Tomcat的7）。但是在我改成tomcat 6之后，球衣就起作用了！

我不知道为什么，但我建议你改变并尝试。

Answer 2

您所需要的只是使用便携式JAX-RS部署方法，如here所述。除了使用包扫描，强制手动扫描使用的javax.ws.rs.core.Application

import java.util.HashSet; 
import java.util.Set; 
import javax.ws.rs.core.Application; 

public class MyApplication extends Application { 
    @Override 
    public Set<Class<?>> getClasses() { 
     final Set<Class<?>> classes = new HashSet<Class<?>>(); 
     // register resources 
     classes.add(MessageResource.class); 
     return classes; 
    } 
} 

实现然后，更新您的web.xml中使用它代替。请记住要禁用resteasy扫描，如下所示。

<?xml version="1.0" encoding="UTF-8"?> 
    <web-app 
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xmlns="http://java.sun.com/xml/ns/javaee" 
     xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
     xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
     id="WebApp_ID" 
     version="2.5"> 

    <display-name>Spil</display-name> 
    <welcome-file-list> 
     <welcome-file>index.html</welcome-file> 
    </welcome-file-list> 

    <servlet> 
     <servlet-name>SpilMessageService</servlet-name> 
     <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class> 

     <init-param> 
      <param-name>javax.ws.rs.Application</param-name> 
      <param-value>net.ussouth.incomm.SPIL.resource.MyApplication</param-value> 
     </init-param> 

     <init-param> 
      <param-name>log4j-properties-location</param-name> 
      <param-value>classes/log4j.xml</param-value> 
     </init-param> 

     <load-on-startup>1</load-on-startup> 
    </servlet> 
    <context-param> 
     <param-name>resteasy.scan</param-name> 
     <param-value>false</param-value> 
    </context-param> 
    <context-param> 
     <param-name>resteasy.scan.providers</param-name> 
     <param-value>false</param-value> 
    </context-param> 
    <context-param> 
     <param-name>resteasy.scan.resources</param-name> 
     <param-value>false</param-value> 
    </context-param> 

    <servlet-mapping> 
     <servlet-name>SpilMessageService</servlet-name> 
     <url-pattern>/*</url-pattern> 
    </servlet-mapping> 

</web-app>