（Python）while循环正在破坏我的随机数

Question

所以我正在做一个项目，它基本上从1 - 6中选择一个随机数作为一个迷你项目。

在大多数情况下，它的工作原理。但是当它回圈时，它似乎继续滚动相同的数字。

这里是我的意思

截图正如你所看到的，骰子数量不断滚动相同。你能看到我的代码中有什么问题吗？

# Useful module for selecting random numbers 
import random 

# Loop program back to here once user presses anything 
loop = 1 

#Chooses random number between 1 - 6 
Random_Number = (random.choice([1,2,3,4,5,6])) 

while (loop < 10): 
    #Printing what the user sees 
    print ("===============================") 
    print ("Your random dice number is:", Random_Number) 
    input("Press any key to roll again") 
    print ("===============================") 

    #looping back to "loop = 1" 
    loop = loop + 1 

Answer 1

您正在生成Random_Number一次，循环外。 尝试类似这样的

while (loop < 10): 
    Random_Number = (random.choice([1,2,3,4,5,6])) 
    #Printing what the user sees 
    print ("===============================") 
    print ("Your random dice number is:", Random_Number) 
    input("Press any key to roll again") 
    print ("===============================") 

    loop = loop + 1 

Answer 2

此代码选择一次随机数，然后只打印10次。如果你想有一个不同的随机数每一次，你应该将随机选择内循环：

while (loop < 10): 
    #Chooses random number between 1 - 6 
    Random_Number = (random.choice([1,2,3,4,5,6])) 

    #Printing what the user sees 
    print ("===============================") 
    print ("Your random dice number is:", Random_Number) 
    input("Press any key to roll again") 
    print ("===============================") 

    #looping back to "loop = 1" 
    loop = loop + 1 

Answer 3

您可以设置RANDOM_NUMBER的价值只有一次，然后显示，每个循环。

固定

# Useful module for selecting random numbers 
import random 

# Loop program back to here once user presses anything 
loop = 1 

#Chooses random number between 1 - 6 
#Random_Number = (random.choice([1,2,3,4,5,6])) 

while (loop < 10): 
    #Printing what the user sees 
    print ("===============================") 
    print ("Your random dice number is:", (random.choice([1,2,3,4,5,6]))) 
    #input("Press any key to roll again") 
    print ("===============================") 

    #looping back to "loop = 1" 

Answer 4

因为您只生成一次随机数。 应该

... 
while (loop < 10): 
    Random_Number = (random.choice([1,2,3,4,5,6])) 
.... 

而且不名的变量有上字母代替RANDOM_NUMBER使用RANDOM_NUMBER

Answer 5

您需要了解的Python（以及类似的语言）存储值，而不是表达式。如果您编写a = 2 + 2，则变量a中不存在加法和不加2;只有数字4.

您的情况完全相同：您认为您将Random_Number定义为旁边的表达式的别名，其中实际上只存储一个数字。

你当然可以通过在循环内调用random.choice()来解决这个问题 - 因为大约有10个答案已经提出。但要做意思是要做的事情，请定义一个函数，以您指定的方式选择一个数字。每次调用函数时都会执行函数体。

def random_number(): 
    return random.choice([1,2,3,4,5,6]) 

while (loop < 10): 
    print("you rolled", random_number()) 
    loop += 1 

Answer 6

如果你不想在每次迭代重新定义一个随机数：

# Useful module for selecting random numbers 
import random 

# Loop program back to here once user presses anything 
loop = 1 

#Chooses random number between 1 - 6 
Random_Number = lambda : random.choice([1,2,3,4,5,6]) 

while (loop < 10): 
    #Printing what the user sees 
    print ("===============================") 
    print ("Your random dice number is:", Random_Number()) 
    print ("===============================") 

    #looping back to "loop = 1" 
    loop = loop + 1