根据新行字符将命令输出行存储到数组中

Question

我有一个变量，如下所示&我执行某些操作来逐个打印输出，如下所述。

a="My name is A. Her Name is B. His Name is C" 
echo "$a" | awk -F '[nN]ame |\\.' '{for (i=2; i<=NF; i+=2) print $i}' 

输出是

is A 
is B 
is C 

当我的结果存储到一个数组，则认为空间阵列分离器和存储的值。但我想输出到每个数组索引值的每一行存储如下

x=($(awk -F '[nN]ame |\\.' '{for (i=2; i<=NF; i+=2) print $i}' <<< "$a")) 

出放，

${x[0]} = is 
${x[1]} = A 
..and so on... 

我期望是

${x[0]} = is A 
${x[1]} = is B 
${x[2]} = is C 

还有echo ${#x[@]} = 6;它应该是= 3

Answer 1

OK try below: 

i=0 
while read v; do 
    x[i]="$v" 
    ((i++)) 
done < <(awk -F '[nN]ame |\\.' '{for (i=2; i<=NF; i+=2) print $i}' <<< "$a") 

Answer 2

也可以使用映射文件命令（bash的版本4或更高）：

tempX=$(awk -F '[nN]ame |\\.' '{for (i=2; i<=NF; i+=2) print $i}' <<< "$a") 
mapfile -t x <<< "$tempX" 

~$ echo "${x[0]}" 
is A