iOS SBJson请求变差

我试图从我的WordPress博客解析JSON提要。我有一个我需要使用的自定义字段，但无法使其与SBJson一起使用。这里是我的饲料看起来像（我已经剥离了其他无用的东西）：iOS SBJson请求变差

{ 
    "status":"ok", 
    "count":27, 
    "count_total":2552, 
    "pages":95, 
    "posts":[ 
     { 
     "id":8978, 
     "type":"post", 



     "custom_fields":{ 

     "btnNameScrollBlog":[ 
      "<null>" 
     ] 
     "author-name":[ 
      "John Doe" 
     ] 
    }, 
}

我想要得到作者的名字。下面是我用于获取在iOS进料的代码：

-(void)downloadRecentPostJson{ 

    [recentPost removeAllObjects]; 
    [previous_total_per_page removeAllObjects]; 


    NSURL *urls = [NSURL URLWithString:[NSString stringWithFormat:@"%@/?json=%@",url,methodJson]]; 
    NSData *sa = [NSData dataWithContentsOfURL:urls]; 
    NSString *jsonString = [[NSString alloc] initWithData:sa encoding:NSUTF8StringEncoding]; 


    NSDictionary *result = [jsonString JSONValue]; 
    NSArray* posts = [result objectForKey:@"posts"]; 
    total_page = [[result objectForKey:@"pages"] intValue]; 
    total_post_per_page = [[result objectForKey:@"count"] intValue]; 

    [previous_total_per_page addObject:[result objectForKey:@"count"]]; 

    current_page = 1; 

    for (NSDictionary *post in posts) { 
     id custom = [post objectForKey:@"custom_fields"]; 
     id thumbnail = [post objectForKey:@"thumbnail"]; 
     NSString *featuredImage = @""; 
     if (thumbnail != [NSNull null]) 
     { 
      featuredImage = (NSString *)thumbnail; 
     } 
     else 
     { 
      featuredImage = @"0"; 
     } 





     [recentPost addObject:[NSArray arrayWithObjects:[post objectForKey:@"id"],[post objectForKey:@"title_plain"],[post objectForKey:@"excerpt"],featuredImage,[post objectForKey:@"content"],[post objectForKey:@"date"],[post objectForKey:@"comments"],[post objectForKey:@"comment_status"],[post objectForKey:@"scrollBlogTemplate"],[post objectForKey:@"url"],[post objectForKey:@"specialBtn"],[post objectForKey:@"btnNameScrollBlog"],[post objectForKey:@"latScrollBlog"],[post objectForKey:@"longScrollBlog"],[post objectForKey:@"openWebUrlScrollBlog"],[post objectForKey:@"gallery"], [custom objectForKey:@"author-name"], nil]]; 

    }

我尝试设置custom_fields对象作为ID：ID定制= [交objectForKey：@ “custom_fields”];

，然后用它去作者的名字：[自定义objectForKey：@ “作者名”]

但我得到一个NSInvalidArgumentException '的，理由是：' - [__ NSArrayM rangeOfString：]：无法识别选择错误。

任何建议？

如果我尝试从帖子中获取类别标题，该怎么办？

"categories": [ 
       { 
        "id": 360, 
        "slug": "deals", 
        "title": "Deals", 
        "description": "", 
        "parent": 0, 
        "post_count": 28 
       } 
      ],

我会把类别放在这样的数组中吗？我如何从那里获得标题？我试过这个，并得到索引3的对象，但有一个错误。

NSArray *cat = [post objectForKey:@"categories"];

来源

2014-02-16 George Ciobanu

错误消息意味着“作者名”是一个NSArray但代码处理它，就好像它是一个NSString。 – Anna

您的Json格式不正确，请尝试使用http://jsonlint.com/ – Hakim

'-[__NSArrayM rangeOfString:]: unrecognized selector error.表示您将数组视为字符串。您的代码几乎是正确的，你只需要得到从阵列（最好用检查数组不为空）的第一个项目，因为

"author-name":[ 
    "John Doe" 
]

是包含一个字符串数组。所以：

NSArray *names = [custom objectForKey:@"author-name"]; 
NSString *name = [names firstObject];

NSArray *categories = [custom objectForKey:@"categories"]; 
NSDictionary *category = [categories firstObject]; 
NSString *title = [category objectForKey:@"title"];

来源

2014-02-16 17:58:57 Wain

您是对的，谢谢！ –

你可以帮助我与类别标题以及？我很困惑。 –

它在哪里嵌套？同样，它包含一个数组，因此您需要索引到数组中以获取字典并使用该键。 – Wain

iOS SBJson请求变差

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