基于两个条件找到所有记录：时间和IP

我想要做的是找到所有具有相同的object_id发生在彼此的秒钟内但具有不同的client_ip地址的记录。基于两个条件找到所有记录：时间和IP

下面是我手动找到的一些例子，但我希望能够识别表中特定日期的所有记录。

SELECT sa.client_ip, sa.action_occured, sa.[object_id] 
--INTO #TmpB 
FROM dbo.system_audit AS [sa] 
WHERE sa.action_id = 9111 AND sa.object_type_id = 9100 
AND sa.[object_id] IN (50017197, 50050471, 50100927,50145858,50144558);

而且结果：

的样本数据可能会帮助比屏幕截图更多：

client_ip      action_occured   object_id 
fe80::7996:b7de:c335:699b%12 2016-12-19 15:54:17.300 50017197 
fe80::e41f:6383:5d0d:7b3%3 2016-12-19 15:54:17.410 50017197 
fe80::e41f:6383:5d0d:7b3%3 2016-12-19 14:54:45.383 50050471 
fe80::2117:63d8:2b67:91ab%12 2016-12-19 14:54:46.303 50050471 
fe80::7996:b7de:c335:699b%12 2016-12-19 15:40:42.467 50100927 
fe80::e41f:6383:5d0d:7b3%3 2016-12-19 15:40:42.763 50100927 
fe80::7996:b7de:c335:699b%12 2016-12-19 14:12:54.147 50144558 
fe80::118c:f37b:336d:c1c0%12 2016-12-19 14:12:54.270 50144558 
fe80::b0de:8ce7:be87:582d%12 2016-12-19 14:20:30.770 50145858 
fe80::149b:f256:e64c:4d59%12 2016-12-19 14:20:31.380 50145858

不知道具体的OBJECT_ID，有没有一种方法，我可以比较记录找到在每个记录的第二秒内确实发生的所有object_id，但具有不同的client_ip？

感谢，

来源

2016-12-22 MISNole

你可以滞后/超前这一个。通过action_occurred命令设置您的结果集，然后让您的查询查看以下行，看看如果datediff小于1000毫秒。会尝试写出查询，但没有提供一个简单的方法来重现它的示例数据。 – dfundako

谢谢@dfundako - 我会检查出LAG/LEAD，但如果您想重现它，我还会添加一些示例数据。 – MISNole

至于建议由dfundako，这里有一个方法，你可以用LAG/LEAD做到这一点（和清晰度CTE）：

WITH augmentedData (client_ip, action_occurred, [object_id], prev_date, prev_ip, next_date, next_ip) 
AS 
(
    SELECT *, 
      LAG(action_occurred, 1) OVER (PARTITION BY [object_id] ORDER BY action_occurred) AS prev_date, 
      LAG(client_ip, 1)  OVER (PARTITION BY [object_id] ORDER BY action_occurred) AS prev_ip, 
      LEAD(action_occurred, 1) OVER (PARTITION BY [object_id] ORDER BY action_occurred) AS next_date, 
      LEAD(client_ip, 1)  OVER (PARTITION BY [object_id] ORDER BY action_occurred) AS next_ip 
    FROM system_audit 
) 

SELECT client_ip, 
     action_occurred, 
     [object_id] 
FROM augmentedData 
WHERE (DATEDIFF(MS,prev_date,action_occurred) < 1000 AND prev_ip <> client_ip) 
    OR (DATEDIFF(MS,action_occurred,next_date) < 1000 AND next_ip <> client_ip) 
ORDER BY action_occurred

来源

2016-12-22 16:09:32 3N1GM4

谢谢你 - 非常有帮助。 – MISNole

基于两个条件找到所有记录：时间和IP

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