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我正在处理angularjs应用程序,并且作为一个新手面临许多问题。我有两个角度的UI网格。基于文本字段中的用户输入,它必须在UI网格中显示值。有艰难的时间来实现这一点。任何的意见都将会有帮助。 请查看我的代码here的演示。根据用户输入显示角度UI网格和值

当用户类型/选择亚特兰大文本字段文本字段和芝加哥和SearchLocations点击按钮,它显示与名义下AtlantaChicago显示值的网格。就像明智的用户输入NewYork和芝加哥一样,它必须显示以名字NewYorkChicago显示的网格值。当文本框中没有输入值时,不应显示网格。任何建议都会非常有帮助。

HTML代码:

<body style="padding-left:15px" ng-controller="searchController"> 
    <form class="form-inline"> 

    <div class="row"> 
     <div class="form-group" ng-controller="citiesCtrl"> 
      <label>From</label> 
      <input type="text" ng-model="places1" placeholder="Type Departure City" typeahead="item for item in items | filter:$viewValue | limitTo:8"> 
     </div> 
     <div class="form-group" ng-controller="citiesCtrl"> 
      <label>To</label> 
      <input type="text" ng-model="places2" placeholder="Type Destination City" typeahead="item for item in items | filter:$viewValue | limitTo:8"> 
     </div> 
    </div> 

    <input type="submit" value="SearchLocations" ng-submit="submit()"> 
    <div ng-repeat="user in users"> 
     <h3>{{user.name}}</h3> 
     <div ui-grid="{ data: user.details }" ng-show="user.show" class="myGrid"></div> 
    </div> 

</form> 
</body> 

JS代码:

angular.module('myApp', ['ngAnimate', 'ui.bootstrap','ngTouch', 'ui.grid', 'ui.grid.selection', 'ui.grid.edit','ui.grid.cellNav']); 
     angular.module('myApp').controller('citiesCtrl',function($scope){ 
      $scope. places = undefined; 
      $scope.items = ["Atlanta", "Chicago", "NewYork"]; 
      $scope.selectAction = function() { 
       console.log($scope.places1); 

      }; 
     }); 

    /*Controller for searchLocations button*/ 
     angular.module('myApp').controller('searchController', ['$scope', function($scope) { 
      $scope.submit = function() { 
       alert("in submit"); 
       if ($scope.places1) { 
        alert("inside the condition"); 
        /*       $scope.list.push(this.places1); 
        $scope.places1 = ''; 
        */      } 
      }; 
      $scope.users = [ 
       {'name' : 'AtlantaChicago', 
        'show' : true, 
        'details' : [ 
         {"Travel Date": "10/10/2014", commute:"Bus"}, 
         {"Travel Date": "10/11/2014", commute:"flight"}] 
       }, 
       {'name' : 'NewYorkChicago', 
        'show' : true, 
        'details': [ 
         {"Travel Date": "3/15/2016", commute:"flight"}, 
         {"Travel Date": "10/12/2016", commute:"flight"}, 
        ] 
       } 
      ]; 
      $scope.gridOptions = { 
       enableFiltering: true, 
       columnDefs: [ 
        { name: 'Travel Date', width: '5%'}, 
        { name: 'Departurecommute', enableFiltering: false, width: '12%' } 
       ], 
       rowHeight: 20, 
       enableHorizontalScrollbar:2 

      }; 
     }]); 

回答

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您需要定义父范围places - searchController。在这种情况下,您的子女(citiesCtrl)会继承他们并在模型更改时进行修改,因此您可以通过父母中的submit()调用访问更改的值。否则每个citiesCtrl将创建它自己的places变量。

Here is your updated example