需要一些帮助PHP的MySQL

Question

这里的问题是

$rd = do_mysql_query("SELECT sum(product_price * '{$count}') as letsee 
         FROM prices 
         WHERE product_id = '{$record['prodid']}' 
         AND id='{$id_p}' 
         ORDER BY product_id") or sqlerr(__FILE__, __LINE__); 
while($row = mysqli_fetch_array($rd)){ 
echo "{$record['prodid']}:{$row['letsee']}<br />"; //id:count 
} 

它为我

10:130 
10:95 
7:88 
6:35 
6:120 
6:330 
11:104 
11:64 

我需要加用ID

所需结果的所有罪名

• 10：225
• 7:88
• 6：485
• 11：168

感谢

Answer 1

您可以用PHP做到这一点：

foreach($records as $record){//First loop or something like it 
    $rd = do_mysql_query("SELECT sum(product_price * '{$count}') as letsee FROM prices WHERE product_id = '{$record['prodid']}' AND id='{$id_p}' ORDER BY product_id") or sqlerr(__FILE__, __LINE__); 
    while($row = mysqli_fetch_array($rd)){ 
     $final_array[$record['prodid']]+=$row['letsee']; //id:count 
    } 
}//End of First loop or something like it 

foreach($final_array as $key => $value){ 
    echo $key.':'.$value; 
} 

注：我认为你应该使用PHP，因为检查你的代码似乎，你有另一个循环得到$record['prodid']和$count这是造成重复。如果您不止一次发送相同的product_id，则无法使用查询来解决此问题。

Answer 2

试试这个

$rd = do_mysql_query("SELECT sum(product_price) as letsee FROM prices WHERE product_id = '{$record['prodid']}' AND id='{$id_p}' GROUP BY product_id ORDER BY product_id") or sqlerr(__FILE__, __LINE__); 
while($row = mysqli_fetch_array($rd)){ 
echo "{$record['prodid']}:" . $row['letsee'] * $count ."<br />"; //id:count 
}