我试图编写一个应用程序，它从本地xml文件中读取，并且需要一些帮助。我已经阅读了这里的一些文章以及google和youtube来读取/写入xml文件，但其中大部分文件都是在线文件。我正在寻找在Android本地读/写xml。到目前为止，我认为，我需要的步骤如下。在Android本地读取XML
我似乎无法得到第一个2的工作。我不是在寻找代码，也不是寻找代码的简单方法。我真的想弄清楚这一点，但需要你们大家在这里的一些指导。我真的无法找到一种方法来读取XML文件。从我在这里找到的，我需要将XML文件放在res/raw文件夹中，然后从那里，我不太确定该怎么做。我如何将它读入数组？一旦我把这个东西运行起来，我会尽我所能发布代码，并希望帮助其他有类似问题的人。再次感谢！
我终于得到它的工作就是我想要的，这里是我试图完成。对所有提供的答案，非常感谢！我拿走了你的每一个模式，并根据需要定制它。我绝不是一个android/java/xml专家，但这是我得到的，它的工作方式我想要！
public class MainActivity extends Activity {
Spinner spinner;
List<String> ingredient = new ArrayList<String>();
List<String> effect1 = new ArrayList<String>();
List<String> effect2 = new ArrayList<String>();
List<String> effect3 = new ArrayList<String>();
List<String> effect4 = new ArrayList<String>();
XmlResourceParser myXml;
int eventType;
String nodeValue;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
loadXml(); // Reads XML and loads it into Lists, One list for each element
convertListToSpinner(); // Takes Lists and merges data with Spinners (Currently Unimplemented)
}
private void convertListToSpinner() {
// TODO Auto-generated method stub
}
private void loadXml() {
// TODO Auto-generated method stub
myXml = getBaseContext().getResources().getXml(R.xml.xmlfilename);
try {
myXml.next();
eventType = myXml.getEventType(); // Get current xml Event
} catch (XmlPullParserException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
while(eventType != XmlPullParser.END_DOCUMENT){
if(eventType == XmlPullParser.START_DOCUMENT){
// checks can be placed here to make sure file is read
}
else if(eventType == XmlPullParser.START_TAG){
nodeValue = myXml.getName();
try{
if(nodeValue.equalsIgnoreCase("Ingredient")){ //Finds Ingredient tag
myXml.next(); //Since the ingredient tag does not hold the text, we go to next element area
ingredient.add(myXml.getText().trim()); // Set the text of the Ingredient tag to list
}
//Since the effect tags are followed by ending tags, we can just do nextText() to get tag text
if(nodeValue.equalsIgnoreCase("Effect1")){
effect1.add(myXml.nextText().trim()); // Set the text of the Effect1 tag to list
}
if(nodeValue.equalsIgnoreCase("Effect2")){
effect2.add(myXml.nextText().trim()); // ditto
}
if(nodeValue.equalsIgnoreCase("Effect3")){
effect3.add(myXml.nextText().trim()); // ditto
}
if(nodeValue.equalsIgnoreCase("Effect4")){
effect4.add(myXml.nextText().trim()); // ditto
}
}catch(Exception e){
e.getMessage();
}
}
try {
eventType = myXml.next();
} catch (XmlPullParserException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
for(int i = 0; ingredient.size() > i; i++){
System.out.println(ingredient.get(i));
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.activity_main, menu);
return true;
}
}
而XML文件是以当前格式。
<?xml version="1.0" encoding="UTF-8"?>
<resources xmlns:android="http://schemas.android.com/apk/res/android" >
<item
name="item"
type="string">
<Ingredient>
Intrests
<effect1>
Android
</effect1>
<effect2>
Programming
</effect2>
<effect3>
Type O Negative
</effect3>
<effect4>
Sirenia
</effect4>
</Ingredient>
<Ingredient>
Virtues
<effect1>
Power
</effect1>
<effect2>
Money
</effect2>
<effect3>
Knowledge
</effect3>
<effect4>
Kindness
</effect4>
</Ingredient>
</item>
</resources>
我希望这可以帮助其他有类似问题的人。再次感谢Sobo和HADEV的贡献！
我敢肯定有做的是做什么工作的一种更好的方式，但我很高兴我得到了这个工作:)
在主类
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.Toast;
public class SimpleList extends Activity { //SimpleList is the name of this class
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
final ListView lv=(ListView)findViewById(R.id.listView1);
//final ArrayList<String> myNewList = new ArrayList<String>();
ArrayAdapter<CharSequence> adapter=ArrayAdapter.createFromResource(this, R.array.simple_array,android.R.layout.simple_list_item_1);
lv.setAdapter(adapter);
lv.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3) {
// TODO Auto-generated method stub
String item=lv.getItemAtPosition(arg2).toString();
String itemordered;
itemordered = item + " added to list";
Toast.makeText(getApplicationContext(), itemordered, Toast.LENGTH_LONG).show();
}
});
}
}
创建的strings.xml一个字符串数组
<resources>
<string name="app_name">SimpleList</string>
<string name="menu_settings">Settings</string>
<string name="title_activity_main">SimpleList</string>
<string-array name="simple_array">
<item>Bacon Double Cheese Burger</item>
<item>Bacon Cheeses Burger</item>
<item>Cheese Burger</item>
<item>Hamburger</item>
<item>Grilled Chicken Sandwich</item>
<item>Crispy Chicken Sandwich</item>
<item>Chicken Strips</item>
<item>Hot Dog</item>
<item>Chocolate Chip Cookie Dough Polar Swirl</item>
<item>Vanilla Shake</item>
<item>Chocolate Shake</item>
<item>Strawberry Shake</item>
</string-array>
</resources>
main.xml中创建您的ListView布局
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
<ListView
android:id="@+id/listView1"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:divider="#FFCC00"
android:dividerHeight="2dp" >
</ListView>
</LinearLayout>
哇，谢谢你的时间和信息。肯定有帮助！ – 2012-07-21 01:09:47
可以使用SAX解析器
种SAX回调方法：
startDocument（）和调用endDocument（） - 调用的方法在XML文档的开始和结束。 startElement（）和endElement（） - 在文档元素的开始和结束处调用的方法。 characters（） - 使用XML文档元素的开始和结束标记之间的文本内容调用的方法。
假设你有这样的XML文件：解析
<?xml version="1.0"?>
<company>
<staff>
<firstname>yong</firstname>
<lastname>mook kim</lastname>
<nickname>mkyong</nickname>
<salary>100000</salary>
</staff>
<staff>
<firstname>low</firstname>
<lastname>yin fong</lastname>
<nickname>fong fong</nickname>
<salary>200000</salary>
</staff>
</company>
java类：
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;
public class ReadXMLFile {
public static void main(String argv[]) {
try {
SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser saxParser = factory.newSAXParser();
DefaultHandler handler = new DefaultHandler() {
boolean bfname = false;
boolean blname = false;
boolean bnname = false;
boolean bsalary = false;
public void startElement(String uri, String localName,String qName,
Attributes attributes) throws SAXException {
System.out.println("Start Element :" + qName);
if (qName.equalsIgnoreCase("FIRSTNAME")) {
bfname = true;
}
if (qName.equalsIgnoreCase("LASTNAME")) {
blname = true;
}
if (qName.equalsIgnoreCase("NICKNAME")) {
bnname = true;
}
if (qName.equalsIgnoreCase("SALARY")) {
bsalary = true;
}
}
public void endElement(String uri, String localName,
String qName) throws SAXException {
System.out.println("End Element :" + qName);
}
public void characters(char ch[], int start, int length) throws SAXException {
if (bfname) {
System.out.println("First Name : " + new String(ch, start, length));
bfname = false;
}
if (blname) {
System.out.println("Last Name : " + new String(ch, start, length));
blname = false;
}
if (bnname) {
System.out.println("Nick Name : " + new String(ch, start, length));
bnname = false;
}
if (bsalary) {
System.out.println("Salary : " + new String(ch, start, length));
bsalary = false;
}
}
};
saxParser.parse("c:\\file.xml", handler);
} catch (Exception e) {
e.printStackTrace();
}
}
}
这可以帮助你http://stackoverflow.com/questions/2728064/parsing-local-xml-file-sax-in-android – HADEV 2012-07-21 01:02:03