我是初学者python prorammer。使用2.7.2,Windows 7,内置解释器和三个库。我试图做到这一点,错误。我感谢任何帮助?IOError:[Errno socket error] [Errno 11004] getaddrinfo失败
import os
import urllib
import socket
DISNEY_URL = 'http://www.sec.gov/Archives/edgar/data/1001039/000119312511321340/dis-20111001.xml'
#Neither of these seem to work when opening with urllib.urlopen becaue of the error:
#I/O error(socket error): [Errno 11004] getaddrinfo failed
DISNEY_LOCAL = 'file://C:/Users/Nate/Desktop/Education/python_education/xbrlnexusfiles/xbrlfiles/dis-20111001.xml'
DISNEY_LOCAL_NONE = 'file://C:/Users/Nate/Desktop/Education/python_education/xbrlnexusfiles/xbrlfiles/dis.txt'
class SECFilingPackage(object):
def __init__ (self, SEC_URL):
URLFilePath, URLFileExt = os.path.splitext(SEC_URL)
try:
urllib.urlopen(SEC_URL)
except IOError as (errno, strerror):
print "I/O error({0}): {1}".format(errno, strerror)
#This error throws, see it copied above;
DisneyPackage = SECFilingPackage(DISNEY_LOCAL_NONE)
我得到这个错误: I/O错误(套接字错误):
[Errno 11004] getaddrinfo failed
是文本文件存在于该位置。该文本文件的内容是“无”
堆栈跟踪说,最后一次通话是线516 open_ftp
C:/Python27/Lib/urllib.py
:
host = socket.gethostbyname(host)
IOError: [Errno socket error] [Errno 11004] getaddrinfo failed
我可以打开网址的很好,所以我不认为这是一个proxy/firewall issue (我也不明白)
而我不明白newlines or ENDs可能与它有什么关系。
我相信它应该是因为工作urllib reference:
If the URL does not have a scheme identifier, or if it has file: as its scheme identifier, this opens a local file (without universal newlines); otherwise it opens a socket to a server somewhere on the network.
(我认为这只是意味着有人谁希望通用换行已经转换那里,会很失望。
注意我也争对部分“如果没有一个方案标识符”,因为如果我不file://
先于字符串,我得到
IOError: [Errno url error] unknown url type: 'c')
我想“学会钓鱼”可以这么说,谁能告诉我有没有一种方法可以调试到urllib.py
以至少了解这些值?我可以用日食来做到吗?它似乎总是迫使我成为一个项目。
http://stackoverflow.com/questions/5022945/urllib2-urlerror-urlopen-error-errno-11004-getaddrinfo-failed – jdi 2012-01-29 17:29:38