不会发送所有参数来发布http请求

Question

我想用java发送一个http请求。这是我的代码：

String AnnonseUrl = "http://webpage.no/insert_annonse.php?info="+info+"&tittel="+tittel+"&bedriftsNavn="+bedriftsNavn+"&kontaktEmail="+kontaktEmail+"&varighet="+varighet+"&frist="+frist+"&url="+url+"&sted="+sted+"&kontaktNavn="+kontaktNavn;    

      URL url = new URL(AnnonseUrl); 
      URLConnection uc = url.openConnection(); 
      BufferedReader in = new BufferedReader(
            new InputStreamReader(
            uc.getInputStream())); 

      in.close(); 

只有前三个参数提交..

如果我COPIE字符串“AnnonseUrl”并粘贴到浏览器，然后一切工作正常。

Answer 1

当执行后的参数在HTTP主体发送： 试试这个：

URL u = new URL("http://www.stackoverflow.com"); 
HttpURLConnection conn = (HttpURLConnection) u.openConnection(); 
conn.setDoOutput(true); 
conn.connect(); 
DataOutputStream wr = new DataOutputStream (
       conn.getOutputStream()); 
wr.writeBytes (urlParameters); 
wr.flush(); 
wr.close(); 

凡urlParameters是一样的东西：

String urlParameters = 
    "tittel="+URLEncoder.encode(tittel,"UTF-8") 
    +"&bedriftsNavn"+URLEncoder.encode(bedriftsNavn,"UTF-8");