我必须检测两个时间段是否重叠。检测重叠时间的算法
每个时期都有开始日期和结束日期。
我需要检测我的第一个时间段（A）是否与另一个（B/C）重叠。
在我的情况下，如果B的开始等于A的结束，他们没有重叠（太倒数）
我发现了以下情况：
所以实际上我这样做这样的：
tStartA < tStartB && tStartB < tEndA //For case 1
OR
tStartA < tEndB && tEndB <= tEndA //For case 2
OR
tStartB < tStartA && tEndB > tEndA //For case 3
（外壳4被取入帐户或者在情况1或情况2）
它作品，但它似乎不是很有效。
因此，首先是在c＃中有一个现有的类，可以对此进行建模（一段时间），类似于timepsan，但具有固定的开始日期。
其次：是否已经有一个C＃代码（如在Datetime类中）可以处理这个？
第三：如果不是，那么您将如何使这个比较最快？
在CodeProject上有一个很好的评论库：http://www.codeproject.com/Articles/168662/Time-Period-Library-for-NET
该库在重叠，相交等方面做了大量工作。它太大而无法复制/粘贴所有内容，但我会看到哪些特定的部分对您有用。
自定义interval-tree结构如何？您必须稍微调整一下，以定义两个区间在您的域中“重叠”的含义。
This question可能会帮助您在C＃中找到现成的间隔树实现。
您可以创建一个可重用的震荡格局类：
public class Range<T> where T : IComparable
{
readonly T min;
readonly T max;
public Range(T min, T max)
{
this.min = min;
this.max = max;
}
public bool IsOverlapped(Range<T> other)
{
return Min.CompareTo(other.Max) < 0 && other.Min.CompareTo(Max) < 0;
}
public T Min { get { return min; } }
public T Max { get { return max; } }
}
您可以添加需要合并范围内的所有方法，得到交叉口等等...
好的答案，但是比较应该返回Min.CompareTo（other.Max）<= 0 && other.Min.CompareTo（Max）<= 0; –
'code' public bool InersectsW –
如何使用IoC注入这个类，比如autofac？ – Sai
我不相信框架本身就有这个类。也许是第三方库...
但为什么不创建一个Period值对象类来处理这种复杂性？这样您可以确保其他约束条件，如验证开始日期和结束日期时间。喜欢的东西：
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Whatever.Domain.Timing {
public class Period {
public DateTime StartDateTime {get; private set;}
public DateTime EndDateTime {get; private set;}
public Period(DateTime StartDateTime, DateTime EndDateTime) {
if (StartDateTime > EndDateTime)
throw new InvalidPeriodException("End DateTime Must Be Greater Than Start DateTime!");
this.StartDateTime = StartDateTime;
this.EndDateTime = EndDateTime;
}
public bool Overlaps(Period anotherPeriod){
return (this.StartDateTime < anotherPeriod.EndDateTime && anotherPeriod.StartDateTime < this.EndDateTime)
}
public TimeSpan GetDuration(){
return EndDateTime - StartDateTime;
}
}
public class InvalidPeriodException : Exception {
public InvalidPeriodException(string Message) : base(Message) { }
}
}
这样，你就能够单独比较每个时期......
试试http://www.codeproject.com/Articles/168662/Time-Period-Library-for-NET –
我建立一个订票系统，发现这个页面。我只对范围交叉感兴趣，所以我建立了这个结构;使用DateTime范围就足够了。
您可以检查交叉口，并检查特定日期是否在范围内，并获取 交叉口类型，最重要的是：您可以获得相交的Range。
public struct DateTimeRange
{
#region Construction
public DateTimeRange(DateTime start, DateTime end) {
if (start>end) {
throw new Exception("Invalid range edges.");
}
_Start = start;
_End = end;
}
#endregion
#region Properties
private DateTime _Start;
public DateTime Start {
get { return _Start; }
private set { _Start = value; }
}
private DateTime _End;
public DateTime End {
get { return _End; }
private set { _End = value; }
}
#endregion
#region Operators
public static bool operator ==(DateTimeRange range1, DateTimeRange range2) {
return range1.Equals(range2);
}
public static bool operator !=(DateTimeRange range1, DateTimeRange range2) {
return !(range1 == range2);
}
public override bool Equals(object obj) {
if (obj is DateTimeRange) {
var range1 = this;
var range2 = (DateTimeRange)obj;
return range1.Start == range2.Start && range1.End == range2.End;
}
return base.Equals(obj);
}
public override int GetHashCode() {
return base.GetHashCode();
}
#endregion
#region Querying
public bool Intersects(DateTimeRange range) {
var type = GetIntersectionType(range);
return type != IntersectionType.None;
}
public bool IsInRange(DateTime date) {
return (date >= this.Start) && (date <= this.End);
}
public IntersectionType GetIntersectionType(DateTimeRange range) {
if (this == range) {
return IntersectionType.RangesEqauled;
}
else if (IsInRange(range.Start) && IsInRange(range.End)) {
return IntersectionType.ContainedInRange;
}
else if (IsInRange(range.Start)) {
return IntersectionType.StartsInRange;
}
else if (IsInRange(range.End)) {
return IntersectionType.EndsInRange;
}
else if (range.IsInRange(this.Start) && range.IsInRange(this.End)) {
return IntersectionType.ContainsRange;
}
return IntersectionType.None;
}
public DateTimeRange GetIntersection(DateTimeRange range) {
var type = this.GetIntersectionType(range);
if (type == IntersectionType.RangesEqauled || type==IntersectionType.ContainedInRange) {
return range;
}
else if (type == IntersectionType.StartsInRange) {
return new DateTimeRange(range.Start, this.End);
}
else if (type == IntersectionType.EndsInRange) {
return new DateTimeRange(this.Start, range.End);
}
else if (type == IntersectionType.ContainsRange) {
return this;
}
else {
return default(DateTimeRange);
}
}
#endregion
public override string ToString() {
return Start.ToString() + " - " + End.ToString();
}
}
public enum IntersectionType
{
/// <summary>
/// No Intersection
/// </summary>
None = -1,
/// <summary>
/// Given range ends inside the range
/// </summary>
EndsInRange,
/// <summary>
/// Given range starts inside the range
/// </summary>
StartsInRange,
/// <summary>
/// Both ranges are equaled
/// </summary>
RangesEqauled,
/// <summary>
/// Given range contained in the range
/// </summary>
ContainedInRange,
/// <summary>
/// Given range contains the range
/// </summary>
ContainsRange,
}
public class ConcreteClassModel : BaseModel
{
... rest of class
public bool InersectsWith(ConcreteClassModel crm)
{
return !(this.StartDateDT > crm.EndDateDT || this.EndDateDT < crm.StartDateDT);
}
}
[TestClass]
public class ConcreteClassTest
{
[TestMethod]
public void TestConcreteClass_IntersectsWith()
{
var sutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 02, 01), EndDateDT = new DateTime(2016, 02, 29) };
var periodBeforeSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 01, 01), EndDateDT = new DateTime(2016, 01, 31) };
var periodWithEndInsideSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 01, 10), EndDateDT = new DateTime(2016, 02, 10) };
var periodSameAsSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 02, 01), EndDateDT = new DateTime(2016, 02, 29) };
var periodWithEndDaySameAsStartDaySutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 01, 01), EndDateDT = new DateTime(2016, 02, 01) };
var periodWithStartDaySameAsEndDaySutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 02, 29), EndDateDT = new DateTime(2016, 03, 31) };
var periodEnclosingSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 01, 01), EndDateDT = new DateTime(2016, 03, 31) };
var periodWithinSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 02, 010), EndDateDT = new DateTime(2016, 02, 20) };
var periodWithStartInsideSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 02, 10), EndDateDT = new DateTime(2016, 03, 10) };
var periodAfterSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 03, 01), EndDateDT = new DateTime(2016, 03, 31) };
Assert.IsFalse(sutPeriod.InersectsWith(periodBeforeSutPeriod), "sutPeriod.InersectsWith(periodBeforeSutPeriod) should be false");
Assert.IsTrue(sutPeriod.InersectsWith(periodWithEndInsideSutPeriod), "sutPeriod.InersectsWith(periodEndInsideSutPeriod)should be true");
Assert.IsTrue(sutPeriod.InersectsWith(periodSameAsSutPeriod), "sutPeriod.InersectsWith(periodSameAsSutPeriod) should be true");
Assert.IsTrue(sutPeriod.InersectsWith(periodWithEndDaySameAsStartDaySutPeriod), "sutPeriod.InersectsWith(periodWithEndDaySameAsStartDaySutPeriod) should be true");
Assert.IsTrue(sutPeriod.InersectsWith(periodWithStartDaySameAsEndDaySutPeriod), "sutPeriod.InersectsWith(periodWithStartDaySameAsEndDaySutPeriod) should be true");
Assert.IsTrue(sutPeriod.InersectsWith(periodEnclosingSutPeriod), "sutPeriod.InersectsWith(periodEnclosingSutPeriod) should be true");
Assert.IsTrue(sutPeriod.InersectsWith(periodWithinSutPeriod), "sutPeriod.InersectsWith(periodWithinSutPeriod) should be true");
Assert.IsTrue(sutPeriod.InersectsWith(periodWithStartInsideSutPeriod), "sutPeriod.InersectsWith(periodStartInsideSutPeriod) should be true");
Assert.IsFalse(sutPeriod.InersectsWith(periodAfterSutPeriod), "sutPeriod.InersectsWith(periodAfterSutPeriod) should be false");
}
}
感谢上述答案，帮助我上面代码中的一个MVC项目。
注StartDateDT和EndDateDT是日期时间类型
此代码检查如果两个区间重叠。
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算法：
x1 < y2
and
x2 > y1
例如12:00 - 12:30未与12:30 13:00
--logic FOR OVERLAPPING DATES
DECLARE @StartDate datetime --Reference start date
DECLARE @EndDate datetime --Reference end date
DECLARE @NewStartDate datetime --New Start date
DECLARE @NewEndDate datetime --New End Date
Select
(Case
when @StartDate is null
then @NewStartDate
when (@StartDate<@NewStartDate and @EndDate < @NewStartDate)
then @NewStartDate
when (@StartDate<@NewStartDate and @EndDate > @NewEndDate)
then @NewStartDate
when (@StartDate<@NewStartDate and @EndDate > @NewStartDate)
then @NewStartDate
when (@StartDate>@NewStartDate and @NewEndDate < @StartDate)
then @NewStartDate
else @StartDate end) as StartDate,
(Case
when @EndDate is null
then @NewEndDate
when (@EndDate>@NewEndDate and @Startdate < @NewEndDate)
then @NewEndDate
when (@EndDate>@NewEndDate and @Startdate > @NewEndDate)
then @NewEndDate
when (@EndDate<@NewEndDate and @NewStartDate > @EndDate)
then @NewEndDate
else @EndDate end) as EndDate
不知道你怎么能比我接受的那个更好地考虑这个答案？ – J4N
重叠试试这个。无论方法的输入参数的顺序如何，此方法将确定（两个）日期跨度是否重叠。这也可以有两个以上的时间跨度中，通过逐一检查每个日期跨径组合为（前3日期跨度，运行span1对span2，span2对span3和span1对span3）：
public static class HelperFunctions
{
public static bool AreSpansOverlapping(Tuple<DateTime,DateTime> span1, Tuple<DateTime,DateTime> span2, bool includeEndPoints)
{
if (span1 == null || span2 == null)
{
return false;
}
else if ((new DateTime[] { span1.Item1, span1.Item2, span2.Item1, span2.Item2 }).Any(v => v == DateTime.MinValue))
{
return false;
}
else
{
if (span1.Item1 > span1.Item2)
{
span1 = new Tuple<DateTime, DateTime>(span1.Item2, span1.Item1);
}
if (span2.Item1 > span2.Item2)
{
span2 = new Tuple<DateTime, DateTime>(span2.Item2, span2.Item1);
}
if (includeEndPoints)
{
return
((
(span1.Item1 <= span2.Item1 && span1.Item2 >= span2.Item1)
|| (span1.Item1 <= span2.Item2 && span1.Item2 >= span2.Item2)
) || (
(span2.Item1 <= span1.Item1 && span2.Item2 >= span1.Item1)
|| (span2.Item1 <= span1.Item2 && span2.Item2 >= span1.Item2)
));
}
else
{
return
((
(span1.Item1 < span2.Item1 && span1.Item2 > span2.Item1)
|| (span1.Item1 < span2.Item2 && span1.Item2 > span2.Item2)
) || (
(span2.Item1 < span1.Item1 && span2.Item2 > span1.Item1)
|| (span2.Item1 < span1.Item2 && span2.Item2 > span1.Item2)
) || (
span1.Item1 == span2.Item1 && span1.Item2 == span2.Item2
));
}
}
}
}
测试：
static void Main(string[] args)
{
Random r = new Random();
DateTime d1;
DateTime d2;
DateTime d3;
DateTime d4;
for (int i = 0; i < 100; i++)
{
d1 = new DateTime(2012,1, r.Next(1,31));
d2 = new DateTime(2012,1, r.Next(1,31));
d3 = new DateTime(2012,1, r.Next(1,31));
d4 = new DateTime(2012,1, r.Next(1,31));
Console.WriteLine("span1 = " + d1.ToShortDateString() + " to " + d2.ToShortDateString());
Console.WriteLine("span2 = " + d3.ToShortDateString() + " to " + d4.ToShortDateString());
Console.Write("\t");
Console.WriteLine(HelperFunctions.AreSpansOverlapping(
new Tuple<DateTime, DateTime>(d1, d2),
new Tuple<DateTime, DateTime>(d3, d4),
true //or use False, to ignore span's endpoints
).ToString());
Console.WriteLine();
}
Console.WriteLine("COMPLETE");
System.Console.ReadKey();
}
期间（C）在案例5中令我困惑。这是否代表不重叠的情况？如果是这样，你是不是分成两部分，案例5 B全部在A之前，案例6 A全部在B之前？ –
是它不重叠。 – J4N
质量好的问题！ – bob