迭代由于我是相当新的JSON和jQuery我挣扎过一个对象,我SOFAR能够用下面的代码加载到迭代:通过JSON对象
$.ajax({
url: source,
dataType: 'json',
success: function(obj) {
// Laat een succes-melding zien wanneer de data goed ingeladen is
console.log("SUCCESS");
},
error: function(obj) {
// Laat een error-melding zien wanneer de data niet goed ingeladen is
alert("ERROR");
},
complete: function(obj) {
console.log(obj);
}
});
不幸的是结构JSON的是我的口味有点复杂,但因为它是一个外部源(通过YQL)没什么,可将其改为:
{
"query": {
"count": 1,
"created": "2013-06-21T11:42:57Z",
"lang": "en-US",
"diagnostics": {
"publiclyCallable": "true",
"url": {
"execution-start-time": "1",
"execution-stop-time": "1868",
"execution-time": "1867",
"proxy": "DEFAULT",
"content": "contentsource"
},
"user-time": "1868",
"service-time": "1867",
"build-version": "37740"
},
"results": {
"viewentries": {
"toplevelentries": "0",
"viewentry": [
{
"date": "2013-06-11",
"noteid": "A2FA",
"position": "1",
"siblings": "0",
"unid": "15D7F7A15C0DAE",
"entrydata": [
{
"columnnumber": "0",
"name": "Datum_van_instantie",
"text": "2013-06-11"
},
{
"columnnumber": "1",
"name": "kopregel",
"text": "Title of newsitem 1"
},
{
"columnnumber": "2",
"name": "tussenkopje",
"text": "Introduction text of newsitem 1"
},
{
"columnnumber": "3",
"name": "broodtekst",
"text": "Content of newsitem 1"
},
{
"columnnumber": "4",
"name": "imagetag",
"text": "Image URL of newsitem 1"
}
]
},
{
"date": "2013-05-29",
"noteid": "A2F6",
"position": "2",
"siblings": "0",
"unid": "9237CD3822ED8DD",
"entrydata": [
{
"columnnumber": "0",
"name": "Datum_van_instantie",
"text": "2013-05-29"
},
{
"columnnumber": "1",
"name": "kopregel",
"text": "Title of newsitem 2"
},
{
"columnnumber": "2",
"name": "tussenkopje",
"text": "Introduction text of newsitem 2"
},
{
"columnnumber": "3",
"name": "broodtekst",
"text": "Content of newsitem 2"
},
{
"columnnumber": "4",
"name": "imagetag",
"text": "Image URL of newsitem 2"
}
]
}
]
}
}
}
}
我想完成的事情是打印类似的东西跟随我的HTML文件中的元素:
Title of newsitem 1
Title of newsitem 2
我肯定从那时起我很高兴从文件中提取剩余的项目。用我想要的东西对我来说是有道理的,在各种obj.viewentry [0]选项上使用$ .each循环,我得到一个未定义的错误。当我尝试访问更具体的例如
$.each(obj.viewentry, function(index, value) {
console.log(this.entrydata[0]);
});
我得到的回报是一个jQuery错误,TypeError:e未定义。虽然我确信最后的代码也是'jQuery for Dummies',但我今天早上搜索的其他答案并没有给我更多的清晰。