提取四字从字符串

比赛我需要提取以下四个字符从下面的字符串匹配：提取四字从字符串

网站：

KPAE 
KPSC 
KPUW 
KRNT 
KSEA 
KSFF 
KSHN 
KTIW

数据：

{"sids": ["24222 1", "452670 2", "PAE 3", "KPAE 5", "USW00024222 6"], "name": "EVERETT SNOHOMISH AP"}, 
{"sids": ["24163 1", "PSC 3", "KPSC 5", "USW00024163 6"], "name": "PASCO TRI CITIES AP"}, 
{"sids": ["94129 1", "PUW 3", "KPUW 5", "USW00094129 6"], "name": "PULLMAN MOSCOW RGNL AP"}, 
{"sids": ["94248 1", "RNT 3", "KRNT 5", "USW00094248 6"], "name": "RENTON MUNI AP"}, 
{"sids": ["24233 1", "457473 2", "SEA 3", "72793 4", "KSEA 5", "USW00024233 6", "SEA 7"], "name": "SEATTLE TACOMA INTL AP"}, 
{"sids": ["94176 1", "SFF 3", "KSFF 5", "USW00094176 6"], "name": "SPOKANE FELTS FLD"}, 
{"sids": ["94227 1", "457585 2", "SHN 3", "KSHN 5", "USW00094227 6", "SHN 7"], "name": "SHELTON SANDERSON FLD"}, 
{"sids": ["94274 1", "TIW 3", "KTIW 5", "USW00094274 6"], "name": "TACOMA NARROWS AP"},

我试图从字符串中提取这些匹配，但是，它们的位置可以从字符串更改为字符串...

试图代码：

awk -F',' '{print $5}'

来源

2017-07-10 arnpry

使用grep -oP：

grep -Po '"\K[A-Z]{4}\b' file 

KPAE 
KPSC 
KPUW 
KRNT 
KSEA 
KSFF 
KSHN 
KTIW

来源

2017-07-10 15:45:40 anubhava

嗨。我怎样才能解决所有匹配'US *' – arnpry

匹配的值嗨，对于缺乏信息抱歉......我正在寻找也提取所有类似于以下内容的值：'USW00024163' – arnpry

然后，您可以使用：'grep -Po'\ bUS \ w * |“\ K [AZ] {4} \ b'file' – anubhava

提取四字从字符串

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