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我的Android应用根据用户名和密码的应用也为JSON发送从PHP文件中读取JSON数据。
我已经达到了什么,现在通过指定的用户名和密码,没有从应用程序发送的用户名和密码怎么..
我的问题是,是否有可能阅读并POST使用JSONParse,我只能读?
请看看在JSONParse方法我已经添加了,因为它不工作多数民众赞成评论的一部分“是否有可能从数据库读取状态发送用户名和密码一起使用JSON”发送及阅读使用JSON
JSONParse
private class JSONParse extends AsyncTask<String, String, JSONObject> {
private ProgressDialog pDialog;
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(fishtank.this);
pDialog.setMessage("Getting Data ...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}
@Override
protected JSONObject doInBackground(String... args) {
/*Temp
SharedPreferences settings = getSharedPreferences("mySettings", Activity.MODE_PRIVATE);
us = settings.getString("storedWifiUser", "");
ps = settings.getString("storedWifiPass", "");
try {
JSONObject json = new JSONObject();
json.put("user", us);
json.put("pass", ps);
postData(json);
} catch (JSONException e) {
e.printStackTrace();} Temp */
JSONParser jParser = new JSONParser();
// Getting JSON from URL
JSONObject json = jParser.getJSONFromUrl(url);
return json;
}
public void postData(JSONObject json) throws JSONException {
HttpClient httpclient = new DefaultHttpClient();
try {
HttpPost httppost = new HttpPost(url);
List<NameValuePair> nvp = new ArrayList<NameValuePair>(2);
nvp.add(new BasicNameValuePair("json", json.toString()));
//httppost.setHeader("Content-type", "application/json");
httppost.setEntity(new UrlEncodedFormEntity(nvp));
HttpResponse response = httpclient.execute(httppost);
Log.i("JSON Response : ",json.toString().trim());
if(response != null) {
InputStream is = response.getEntity().getContent();
//input stream is response that can be shown back on android
}
}catch (Exception e) {
e.printStackTrace();
}
}
//Temp
@Override
protected void onPostExecute(JSONObject json) {
pDialog.dismiss();
try {
// Log.i("JSON Response : ",json.toString().trim());
// Log.i("JSON Response : "+json.toString().trim());
// System.out.println("JSON Response : "+json.toString().trim());
JSONObject c = json.getJSONObject("status");
String tog1="";
String tog2="";
String tog3="";
if(c.has("fil"))
tog1 = c.getString("fil");
if(c.has("HEA"))
tog2 = c.getString("HEA");
if(c.has("LED"))
tog3 = c.getString("LED");
Log.i("JSON Response : ",json.toString().trim());
if(tog1.equals("ON"))
{ toggle1.setChecked(true);}
else{ toggle1.setChecked(false);}
if(tog2.equals("ON"))
{ toggle2.setChecked(true);}
else{ toggle2.setChecked(false);}
if(tog3.equals("ON"))
{ toggle3.setChecked(true);}
else{toggle3.setChecked(false);}
} catch (JSONException e) {
e.printStackTrace();
}
}
}//End Json
PHP文件
<?php
$con=mysqli_connect("localhost","root","123","pet_home");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// if(isset($_POST['json'])){
// $json=$_POST['json'];
// $data2=json_decode($json,TRUE);
// $u=$data2->{'user'};
// $p=$data2->{'pass'};
$result = mysqli_query($con,"SELECT * FROM users WHERE username='osama' AND password='123'");
$row_cnt = mysqli_num_rows($result);
//$row_cnt=1;
if($row_cnt>0){
$row = mysqli_fetch_array($result);
$data = array('success'=>true, 'error'=>'', 'status'=>array("fil" => $row['filter_st'], "HEA"=> $row['heat_st'], "LED" =>$row['led_st']));
}else{
$data = array('success'=>false, 'error' => 'No records found');
}
// }else{
// $data = array('success'=>false, 'error' => 'No POST value from Android App');
// }
echo json_encode($data);
mysqli_close($con);
?>
我不想救他们,我只是想沿着侧读取状态发送用户名和密码 – user1928775
ü希望只读JSON数据.... PLZ发布乌尔JSON文件数据 –
JSON数据作为对象PHP文件 – user1928775