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我不明白为什么日食希望我删除“;”并用“,”替换它。变量声明问题
numberOfTimes1 = numberOfTimes + numberOfDelayTimes;
我猜这是一些简单的语法,我忘了。你能否解释一下为什么这样做以及如何解决这个问题。 整个程序
public class Spam {
public static void main(String[] args) {
//1- Taking an instance of Timer class.
Timer timer = new Timer("Printer");
//2- Taking an instance of class contains your repeated method.
timeso t = new timeso();
timer.schedule(t, 0, 10);
}
}
class timeso extends TimerTask {
//times member represent calling times.
private int times = 0;
int time = 6; //How long do you wish for the spamming to run?
int numberOfTimes = time * 100;
int delayTime = 5; //How long do you wish for the program to wait before spamming?
int numberOfDelayTimes = delayTime * 100;
numberOfTimes = numberOfTimes + numberOfDelayTimes;
String spam;
Random randomGenerator = new Random();
public void run() {
times++;
if (times >= numberOfDelayTimes && times <= numberOfTimes+numberOfDelayTimes) {
try {
Robot typer = new Robot();
//for(int x = 1;x <=randomGenerator.nextInt(5); x++){
// spam = spam + randomGenerator.nextInt(10);
//}
byte[] bytes = "spam".getBytes();
//byte[] bytes = spam.getBytes();
for (byte b : bytes){
int code = b;
// key code only handles [A-Z] (which is ASCII decimal [65-90])
if (code > 96 && code < 123) code = code - 32;
typer.delay(10/bytes.length+1);
typer.keyPress(code);
typer.keyRelease(code);
}
if(times % (randomGenerator.nextInt(25)+1) == 0){
typer.delay(10/bytes.length+1);
typer.keyPress(KeyEvent.VK_ENTER);
typer.keyRelease(KeyEvent.VK_ENTER);
}
}
catch (AWTException e){
}
} else {
if (times >= numberOfTimes){
try{
Robot typer = new Robot();
typer.delay(10);
typer.keyPress(KeyEvent.VK_ENTER);
typer.keyRelease(KeyEvent.VK_ENTER);
} catch(Exception e){
}
//Stop Timer.
this.cancel();
}
}
}
}
我不能把声明代码放入运行,因为它会将numberOfTimes保留为1.我会在哪里放置代码? –
@Cammy_the_block:在你尚未但需要创建的构造函数中。 –
如果我在构造函数中有这些声明run()会如何访问它? –