检查互联网连接OKHTTP

我正在使用以下代码进行api调用，并根据收到的响应将用户引导至页面。我如何检查互联网连接？检查互联网连接OKHTTP

我使用的是OK的HTTP客户端和我的代码如下所示：

button.setOnClickListener(new View.OnClickListener() { 
     @Override 
     public void onClick(View v) { 
      String url = "https://xxxxxxxx/" + orderLineId; 
      JSONObject jSon = new JSONObject(); 
      try { 
       jSon.put("prescription_xxxxx", prescriptionIntervalId); 
       jSon.put("prescription_xxxxxxx", false); 
      } catch (JSONException e) { 
       e.printStackTrace(); 
      } 
      String data = jSon.toString(); 
      RequestBody body = RequestBody.create(JSON, data); 
      Request request = new Request.Builder() 
        .url(url) 
        .addHeader("Content-Type", "application/json") 
        .addHeader("Authorization", token) 
        .addHeader("Accept", "application/json") 
        .put(body) 
        .build(); 

      client.newCall(request).enqueue(new Callback() {@Override 
       public void onFailure(Request request, IOException e) { 

        AlertDialog.Builder dialog = new AlertDialog.Builder(AutoRefillActivity.this); 
        dialog.setMessage("Something went wrong. Check connection.") 
          .setCancelable(false) 
          .setPositiveButton("OK", new DialogInterface.OnClickListener() { 
           public void onClick(DialogInterface dialog, int id) { 
            onBackPressed(); 
           } 
          }); 
        AlertDialog alert = dialog.create(); 
        alert.show(); 
       } 

       @Override 
       public void onResponse(Response response) throws IOException { 

        if(response.code()==401){ 

         AlertDialog.Builder dialog = new AlertDialog.Builder(AutoRefillActivity.this); 
         dialog.setMessage("Device was idle for too long please login again.") 
           .setCancelable(false) 
           .setPositiveButton("OK", new DialogInterface.OnClickListener() { 
            public void onClick(DialogInterface dialog, int id) { 
             onBackPressed(); 
            } 
           }); 
         AlertDialog alert = dialog.create(); 
         alert.show(); 

        } 
        else { 

         Intent paymentSummary = new Intent(AutoRefillActivity.this,PPPaymentSummaryActivityNew.class); 
         paymentSummary.putExtra(PPPaymentSummaryActivityNew.EXTRA_ORDER,String.valueOf(orderLineId)); 
         paymentSummary.putExtra("order_line_id",orderLineId); 
         paymentSummary.putExtra(PPPaymentSummaryActivityNew.EXTRA_CATEGORY_CODE,categoryCode); 
         paymentSummary.putExtra("prescriptionIntervalId",prescriptionIntervalId); 
         paymentSummary.putExtra("available",available); 
         paymentSummary.putExtra("token",token); 
         Bundle newBundle = new Bundle(); 
         newBundle.putParcelable(PPPaymentSummaryActivityNew.EXTRA_PRODUCT,product); 
         paymentSummary.putExtras(newBundle); 
         startActivity(paymentSummary); 

        } 
       }

虽然我已经把一个警告框在onFailure处异步请求。这是行不通的。我仍然可以关闭互联网和我的应用程序崩溃。任何解决方案？

来源

2016-11-02 Ackman

嗨，你有没有解决HttpStatusCode问题？我遇到了同样的问题......谢谢。 –

以下方法将确定网络是否可用

/** 
* 
* @param context 
* @return true if connected to Internet 
* 
*/ 
public static boolean isNetworkAvailable(final Context context) { 
    final ConnectivityManager cm = (ConnectivityManager) 
      context.getSystemService(Context.CONNECTIVITY_SERVICE); 
    if (cm == null) return false; 
    final NetworkInfo networkInfo = cm.getActiveNetworkInfo(); 
    // if no network is available networkInfo will be null 
    // otherwise check if we are connected 
    return (networkInfo != null && networkInfo.isConnected()); 
}

然后做你的web服务类的东西

if(isNetworkAvailable(context)){ 
    //do something 
}

来源

2016-11-02 20:31:34

这个问题已经回答了100万次之前。使用搜索 - 结果会是怎样

private boolean isNetworkConnected() { 
    ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE); 

    return cm.getActiveNetworkInfo() != null; 
}

来源

2016-11-02 20:29:55

检查互联网连接OKHTTP

回答

相关问题