如何将数据插入位数据类型的字段？

Question

我试图插入新记录插入数据库时​​有问题。我认为问题在于位域。当我给你的价值真的，我得到这个错误：

Failed: Array ([0] => Array ([0] => 22018 [SQLSTATE] => 22018 [1] 
=> 245 [code] => 245 [2] => [Microsoft][SQL Server Native Client 10.0] 
[SQL Server]Conversion failed when converting the varchar value ' 1 ' 
to data type bit. [message] => [Microsoft][SQL Server Native Client 10.0] 
[SQL Server]Conversion failed when converting the varchar value ' 1 ' to 
data type bit.)) 

，但如果我将其更改为false它的工作原理。我会显示一些我的代码。我把它的大部分缩小了，因为我已经缩小到这个变量了：

$active = True; 

这里是我的插入查询。

$sqlInsert = "INSERT INTO customers(
       customerID, 
       registeredDate, 
       givenName, 
       familyName, 
       email, 
       password, 
       phone, 
       mobile, 
       property, 
       street, 
       locality, 
       town, 
       area, 
       postalCode, 
       active 
      ) 
      VALUES(" . 
       $newUser . "," . 
       $date . ", ' " . 
       $given . " ', ' " . 
       $family . " ', ' " . 
       $email . " ', ' " . 
       $pwd . " ', ' " . 
       $phone . " ', ' " . 
       $mob . " ', ' " . 
       $property . " ', ' " . 
       $street . " ', ' " . 
       $locality . " ' , ' " . 
       $town . " ', ' " . 
       $area . " ', ' " . 
       $postalcode . " ', ' " . 
       $active . " ')"; 

$stmtInsert = sqlsrv_query($conn, $sqlInsert); 

Answer 1

我假定active字段是bit数据类型。

不要使用围绕价值的任何引号传递一个像你这样的客户ID字段做什么活动现场。

另外，我觉得你的价值真/假转换为/。

修改后的代码：注意到围绕" . $active . "的单引号已被删除。

$sqlInsert = "INSERT INTO customers(customerID, registeredDate, givenName, 
       familyName, email, password, 
       phone, mobile, property, 
       street, locality, town, 
       area, postalCode, active) 
       VALUES(" . $newUser . "," . $date . ", ' " . $given . " ', 
       ' " . $family . " ', ' " . $email . " ', ' " . $pwd . " ', 
       ' " . $phone . " ', ' " . $mob . " ', ' " . $property . " ', 
       ' " . $street . " ', ' " . $locality . " ' , ' " . $town . " ', 
       ' " . $area . " ', ' " . $postalcode . " ', " . $active . ")"; 
$stmtInsert = sqlsrv_query($conn, $sqlInsert); 

我不知道为什么它与假价值的工作。我建议您在设置完所有值后，了解INSERT语句的计算结果。不是执行语句，而是将INSERT语句打印到屏幕/页面，并在SQL Server Management Studio中针对数据库手动运行它。