我借助github将csv文件中的数据解析为字典。
解析我得到这种类型的词典后: -在swift中解析CSV文件
{
"" = "";
"\"barred_date\"" = "\"\"";
"\"company_id\"" = "\"1\"";
"\"company_name\"" = "\"\"";
"\"contact_no\"" = "\"1234567890\"";
"\"created_date\"" = "\"2015-06-01 12:43:11\"";
"\"current_project\"" = "\"111\"";
"\"designation\"" = "\"Developer\"";
"\"doj\"" = "\"2015-06-01 00:00:00\"";
"\"fin_no\"" = "\"ABC001\"";
"\"first_name\"" = "\"sssd\"";
"\"last_name\"" = "\"dd\"";
"\"project_name\"" = "\"Project 1\"";
"\"qr_code\"" = "\"12345678\"";
"\"resignation_date\"" = "\"\"";
"\"status\"" = "\"1\"";
"\"work_permit_no\"" = "\"ssdda11\"";
"\"worker_id\"" = "\"1\"";
"\"worker_image\"" = "\"assets/uploads/workers/eb49364ca5c5d22f11db2e3c84ebfce6.jpeg\"";
"\"worker_image_thumb\"" = "\"assets/uploads/workers/thumbs/eb49364ca5c5d22f11db2e3c84ebfce6.jpeg\"";}
我怎样才能将其转换为简单的字典。我需要的数据这样的“COMPANY_ID” =“1”
感谢
这似乎是一个非常简单的CSV阅读器,它根本不处理引用的字段。例如,“a,b”,“c,d”应该被看作带有内容“a,b”和“c,d”(不带引号)的内容的两个*字段。从SwiftCSV快速浏览一下,在我看来,这是不正确的处理。 –
你可以建议我任何其他解析器,这将简单易用... – chakshu
对不起,我没有任何建议。 –