Hex:[0A][52][08][01][01][01][00][CD][21][02][59]
0 [0A]
1 [52] Packettype = TEMP_HUM
2 [08] subtype = TH8 -
3 [01] Sequence nbr = 1
4/5 [01][01] ID = 257
6/7 [00][CD] Temperature = 20.5 °C
8 [21] Humidity = 33
9 [02] Status = Dry
10 [5] *nibble Signal level = 5
11 [9] *nibble Battery = OK
因此,我通过串口获得了11个字节(十六进制)。 我将所有字节分配给一个字节数组,以便稍后使用它们。从Java字节中提取半字节
我有两个qestions:
1]我如何能在4 & 5个字节组合到一起在Java中(我假设在INT)? 2]如何提取10和11或最后一个字节的高位和低位?
[FROM COMMENTS下文] 例字节:高[0101] [0110]低 lowNibble = yourbyte &为0x0F; 为0x0F(00001111)= 00000110
highNibble = yourByte >>>> 4
01010110 >>> 4 = 00000101
IF you use this Example Byte: High[1101][0110]Low
highNibble = yourByte >>> 4
11010110 >>> 4 = 00000101
Because >>> removes the signed bit.
其实我只知道如何将签名字节变成无符号字节int anUnsignedByte =(int)b & 0xff;但我真的不知道发生了什么。 – DevilCode
是的。请注意它是>>>而不是>>>> – Eduardo