我在尝试修改使用ActionBarSherlock
SearchView$SearchAutoComplete
的open source dictionary project。例如,我有一个名为“Google Play”的条目。当我输入“Google”时,SearchView
能够返回建议,但如果我搜索“播放”,情况并非如此。如何使SearchView
能够搜索包含文本的条目?在SearchView中搜索包含特定字符的文本AutoCompleteTextView
public boolean onQueryTextChange(String newText) {
if (MdxDictBase.isMdxCmd(newText)){
currentEntry.setEntryNo(DictEntry.kSystemCmdEntryNo);
}
if (!skipUpdateEntryList) {
dict.locateFirst(newText, true, true, true, false, currentEntry);
syncHeadwordList();
}
skipUpdateEntryList = false;
return true; //return false if want the system provide a suggestion list?
}
完整的代码可以found here。
而这是Cursor
查询其中我found from here。
public Cursor query(Uri uri, String[] projection, String selection, String[] selectionArgs, String sortOrder) {
Log.d(TAG, "Got query:" + uri.toString());
if (uri.getPath() != null && uri.getPath().startsWith(SEARCH_PATH)) {
if (fCurrentDict != null && fCurrentDict.isValid()) {
String query=uri.getLastPathSegment();
if (query!=null && query.length()>0){
DictEntry entry = new DictEntry(0, "", fCurrentDict.getDictPref().getDictId());
if (query != null && query.length() > 0)
fCurrentDict.locateFirst(query, true, false, true, false, entry);
if (entry.isValid()) {
String limit = uri.getQueryParameter(SearchManager.SUGGEST_PARAMETER_LIMIT);
int maxResultCount = 20;
if (limit != null && limit.length() > 0) {
try {
maxResultCount = Integer.parseInt(limit);
} catch (NumberFormatException e) {
e.printStackTrace();
}
}
ArrayList<DictEntry> entryList = new ArrayList<DictEntry>();
fCurrentDict.getEntries(entry, maxResultCount, entryList);
String[] columns = new String[]{
BaseColumns._ID,
SearchManager.SUGGEST_COLUMN_TEXT_1,
SearchManager.SUGGEST_COLUMN_INTENT_DATA_ID,
SearchManager.SUGGEST_COLUMN_SHORTCUT_ID};
MatrixCursor cursor = new MatrixCursor(columns, maxResultCount);
Object[] row;
for (DictEntry cur_entry : entryList) {
String intentDataId = String.format("%d_%d_%s", cur_entry.getDictId(), cur_entry.getEntryNo(), cur_entry.getHeadword());
row = new Object[]{cur_entry.hashCode(), cur_entry.getHeadword(), intentDataId, SearchManager.SUGGEST_NEVER_MAKE_SHORTCUT};
cursor.addRow(row);
}
return cursor;
}
}
}
}
return null;
}
这是locateFirst
方法,该方法我found from here。
/**
* Locates the first entry that match the specified headword
*
* @param headword Headword to be searched for
* @param convertKey Convert the given headword into different Chinese form according to dictionary settings?
* @param partialMatch Match partial of the headword. For example "abc" can be matched with "abd" headword search
* @param entry The matched entry if found
* @return Return kMdxSuccess when succeed, otherwise return error codes.
*/
public synchronized int locateFirst(String headword, boolean convertKey, boolean partialMatch, boolean startWithMatch, boolean bestMatch, DictEntry entry) {
if (isValid()) {
return locateFirstN(headword, convertKey, partialMatch, startWithMatch, bestMatch, entry);
} else {
return kMdxDatabaseNotInited;
}
}
这是我认为这是负责任的,以显示建议的列表中选择适配器: https://bitbucket.org/raymanzhang/mdict-android-opensource/src/eba7b9b4ead17a5b3e027da4a37dbd4ee1162596/src/cn/mdict/widgets/MdxAdapter.java?at=master&fileviewer=file-view-default
你发布的代码没有显示任何过滤迹象。应该有一个类或一些代码,根据来自'searchView'的输入字符串进行过滤。查找从'searchView'获取字符串的代码,并将其作为搜索查询传递,可能在'onTextChanged'回调中,并将其代码和任何与其相关的代码发布以进一步帮助您。 – ahasbini
添加您的搜索代码。它没有足够的代码。 – ADM
我编辑了我的问题。 – user2872856